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Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter11: Data Analysis And Probability

Section: Chapter Questions

Problem 6CST

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The degrees of freedom for a chi square test of a contingency table with 5 rows and 3 columns

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A study using the chi-square test of Independence has 3 categories of one variable and 2 categories for its other variable. What are the degrees of freedom for the study?
How large does a contingency table need to be for statistical analysis? at least 2 rows, 2 columns (2x2) Oat least 2x3 at least 4x2 at least 10x10
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Student Absences and Grades on the Final Exam Dr. V. noticed that the more frequently a student is late or absent from class the worse he or she performs on the final exam. He decided to investigate. Dr. V. collected a random sample of 22 students. This sample includes the number of times a student is absent and their grades on the final exam. The data can be found in the Excel file Assignment10.xlsx. Do not use any software that I did not assign. Question 1: Which or the two variables (times absent or grades on the final exam) is the independent variable and which is the dependent variable? Question 2: Using Microsoft Excel: SHOW YOUR WORK Times Late/Absent Final Exam Grade 1 9 84.00 2 2 92.50 3 12 52.00 4 5 87.00 5 11 75.00 6 24 45.00 7 7 39.00 8 10 46.00 9 19 63.00 10 2 65.00 11 2 98.00 12 17 24.50 13 8 58.00 14 20 69.50 15 55 49.00 16 23 68.50 17 6 70.00 18 4 75.50 19 2 85.00 20 7 97.00 21 2 97.00 22 2 93.50 23 0 93.50 24 2…
(-4.56,-1.64) is incorrect answer. I got it wrong twice. Please do it correctly. I will rate with 4votes. Do correctly please.
The number of degrees of freedom for a chi-square test is calculated as a. n-1. b. n+1. c. (rows-1) + (columns-1). d. (rows-1)(columns-1).
Reading is fundamental to a teenager's ability to perform well in school. Assume a researcher is interested in the ability of the number of books read over the summer to predict ACT Reading scores. Using a random sample of 10 random high school students the researchers recorded the number of books read over the summer and the students' ACT Reading scores. Books Read (X) ACT Score (Y) (X- Xmean) (Y - Ymean) (X-Xmean)(Y-Ymean) (X-Xmean)? (Y - Ymean)? 2 16 -5.4 -14.9 81 29 221 2 19 -5.4 -11.9 64 29 141 3 17 -4.4 -13.9 61 20 192 4 25 -3.4 -5.9 20 12 34 21 -3.4 -9.9 34 12 97 24 -1.4 -6.9 10 2 47 6 21 -1.4 -9.9 14 2 97 8 24 0.6 -6.9 -4 47 7 27 -0.4 -3.9 2 15 10 22 2.6 -8.9 -23 7 78 Total 52 216 259.1 113.3 969.3 МEAN 7.4 30.9 a. Identify the regression line using the number of books read to predict ACT Reading score. Use a = .05 to evaluate the quality of the prediction of the regression line. b. What is the predicted ACT Reading score when 5 books are read?
You are doing a one way analysis of variance on the fuel consumption of different makes of cars. You measure the fuel consumption of 61 cars in total. The number of car makes is 6 for this experiment. How many degrees of freedom does the sum of squares errors have?
Basketball players can take shots worth 3 points, 2 points, or 1 point. A scout is assessing two players- Tabitha and Lauren-who play for different teams in different leagues. The scout wonders if they have similar or different shot selections. They take a random sample of Tabitha's games and a separate random sample of Lauren's games. They tally how many of each type of shot the players attempted in those games. Here is a summary and the results of a chi-square test: Chi-square test: Shot vs. player Tabitha Lauren 3-point 8 12 Expected 10.34 9.66 2-point 40 37 Expected 39.83 37.17 1-point 12 Expected 9.83 9.17 x² = 2.097, DF = 2, P-value = 0.350 %3D Assume that all conditions for inference were met. At the a = 0.05 significance level, what is the most appropriate conclusion to draw from this test? Choose 1 answer: This is convincing evidence that the distribution of shot type differs between Tabitha and Lauren.
Basketball players can take shots worth 3 points, 2 points, or 1 point. A scout is assessing two players- Tabitha and Lauren-who play for different teams in different leagues. The scout wonders if they have similar or different shot selections. They take a random sample of Tabitha's games and a separate random sample of Lauren's games. They tally how many of each type of shot the players attempted in those games. Here is a summary and the results of a chi-square test: Chi-square test: Shot vs. player Tabitha Lauren 3-point 8 12 Expected 10.34 9.66 2-point 40 37 Expected 39.83 37.17 1 point 12 7. Expected 9.83 9.17 X=2.097, DF 2, P-value 0.350 Assume that all conditions for inference were met. At the a=0.05 significance level, what is the most appropriate conclusion to draw from this test? O This is convincing evidence that the distribution of shot type differs between Tabitha and Lauren. O They lack evidence to say that shot type and player are not independent. O This is convincing…

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