The decay of U-238 to Pb-206 can be used to estimate the age of inorganic matter. The half-life of U-238 is 4.5 X 100 years. In a particular rock sample, the ratio of the numbers of Pb-206 to U-238 atoms is 0.66. Assume all of the Pb-206 present is due to the decay of U-238. What is the age of the rock? -kt C=Co e .693 .693 -10 Ty2: K= = 1.54 X10 K 4.5 110
The decay of U-238 to Pb-206 can be used to estimate the age of inorganic matter. The half-life of U-238 is 4.5 X 100 years. In a particular rock sample, the ratio of the numbers of Pb-206 to U-238 atoms is 0.66. Assume all of the Pb-206 present is due to the decay of U-238. What is the age of the rock? -kt C=Co e .693 .693 -10 Ty2: K= = 1.54 X10 K 4.5 110
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
![The decay of U-238 to Pb-206 can be used to estimate the age of inorganic matter. The half-life of U-238 is \(4.5 \times 10^9\) years. In a particular rock sample, the ratio of the numbers of Pb-206 to U-238 atoms is 0.66. Assume all of the Pb-206 present is due to the decay of U-238. What is the age of the rock?
Equation: \( C = C_0 \, e^{-kt} \)
Half-life equation: \( T_{1/2} = \frac{0.693}{k} \)
Decay constant: \( k = \frac{0.693}{4.5 \times 10^9} = 1.54 \times 10^{-10} \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4ce8b870-93ef-497a-8c2a-bbbd1041dd5b%2F9205b27c-acde-44eb-947d-eb63c0d0f02c%2Fnd0pvbe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The decay of U-238 to Pb-206 can be used to estimate the age of inorganic matter. The half-life of U-238 is \(4.5 \times 10^9\) years. In a particular rock sample, the ratio of the numbers of Pb-206 to U-238 atoms is 0.66. Assume all of the Pb-206 present is due to the decay of U-238. What is the age of the rock?
Equation: \( C = C_0 \, e^{-kt} \)
Half-life equation: \( T_{1/2} = \frac{0.693}{k} \)
Decay constant: \( k = \frac{0.693}{4.5 \times 10^9} = 1.54 \times 10^{-10} \)
Expert Solution
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Step 1: Calculation of decay constant
The decay of the U - 238 to Pb - 206 is used to estimate the age of the inorganic matter .
The half ife of U-238 is given to be 4.5 x 109 years
Given the ratio of the numbers Pb- 206 and U-238 atoms is 0.66
Assuming all the Pb - 206 present is due to the decay of U-238
To Find
Age of the rock
Step by step
Solved in 4 steps with 4 images
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