The dataset TrafficFlow gives the delay time in seconds for 24 simulation runs in Dresden, Germany, comparing the current timed traffic light system on each run to a proposed flexible traffic light system in which lights communicate traffic flow information to neighboring lights. On average, public transportation was delayed 105 seconds under the timed system and 44 seconds under the flexible system. Since this is a matched pairs experiment, we are interested in the difference in times between the two methods for each of the 24 simulations. For the n = 24 differences D, we were given that Ip = 61 seconds with sp = 15.19 seconds. We wish to estimate the average time savings for public transportation on this stretch of road if the city of Dresden moves to the new system. The standard error is 3.1 for one set of 10,000 bootstrap samples. Find a 95% confidence interval for the average time savings. Click here for the dataset associated with this question. Round your answers to one decimal place. The 95% confidence interval is i to i

The dataset TrafficFlow gives the delay time in seconds for 24 simulation runs in Dresden, Germany, comparing the current timed traffic light system on each run to a proposed flexible traffic light system in which lights communicate traffic flow information to neighboring lights. On average, public transportation was delayed 105 seconds under the timed system and 44 seconds under the flexible system. Since this is a matched pairs experiment, we are interested in the difference in times between the two methods for each of the 24 simulations. For the n = 24 differences D, we were given that Ip = 61 seconds with sp = 15.19 seconds. We wish to estimate the average time savings for public transportation on this stretch of road if the city of Dresden moves to the new system. The standard error is 3.1 for one set of 10,000 bootstrap samples. Find a 95% confidence interval for the average time savings. Click here for the dataset associated with this question. Round your answers to one decimal place. The 95% confidence interval is i to i

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

An apartment management company wants to explore the consequences of allowing residents to have multiple dogs. They would like to find out whether the number of dogs predicts resident ratings. They would also like to control for the year the apartment complex was built because that might also affect the resident rating. They have collected data on several of their existing complexes. For each complex, they have counted the number of dogs currently living in the complex, the year the complex was built, and the average rating for that particular complex. They would like to perform a multiple regression on these variables to predict resident ratings. See data below. These data are the same as the previous question. Positive and Negative Dog Ratings Number of dogs Year of facility Rating (out of 5) 54 1975 2 31 1964 3.5 0 2015 4.8 11 2011 3.8 73 1964 2.3 23 2016 3.7 0 2015 4.7 49 1989 2.7 What can we conclude about this multiple regression analysis? Fill in the…
StarHortons Cup, the coffee company, wants to determine how long caffeine lasts throughout the day when individuals have a cup of one of their 3 types of coffee at 9am. They will then measure the levels of caffeine in these individuals’ systems at 10am, 12am, 2pm, 4pm, 6pm and 8pm. They want to have at least 20 observations per group. How many separate/distinct groups of participants are needed if they want to conduct this experiment using a mixed-measures ANOVA? 18 6 20 3
When a sample contains 100 or more cases, what is the correct probability distribution to use?
In a study of how depression may affect one's ability to survive a heart attack, the researchers reported the ages of the two groups they examined. The mean age of 2397 patients without cardiac disease was 69.8 years, while for the 450 patients with cardiac disease, the mean age was 74.0, respectively. Furthermore, 32% of the diseased group were smokers, compared with only 23.7% of those free of heart disease. (1) Determine a 96% confidence interval for the difference in the proportions of smokers in the two groups. (ii) Indicate whether the two groups in the study were different. State the assumptions in order to proceed with the confident interval construction. (ii)
The assessment of diet is an important exposure for many disease outcomes. However, there is often much imprecision in dietary recall. In one study, 70-to 79-year-old women were asked about the preschool diet of their children (ages 2−4) using a food frequency questionnaire (FFQ). A unique aspect of the study is that simultaneous diet record data exist on the same children recorded in real time by their mothers when they were ages 2−4 and their mothers were 20 to 40 years old. The data in Table 11.36 were available on average servings of margarine per week. ID FFQ DR 340 7 0 399 7 0.5 466 0 0 502 0 0 541 0 0 554 7 2.5 558 7 3 605 7 0.5 611 21 3.7 618 0 2.5 653 21 4.1 707 7 8.5 The Pearson correlation between intake from the two re-cording methods was 0.448. Assume that FFQ and DR margarine intake are normally distributed. Question: Provide a 95% confidence interval for ρ. #95% CI for z r <- 0.448 #Fisher's transformation of rz <-…
Suppose you were presented with the results of a study comparing two different training methods for basketball athletes. You are told 32 athletes were randomly assigned to the two groups so that 16 were in the group A and 16 were in the group B. At the end of the session, the average scores (wins versus losses) of the two groups/teams were compared and a difference of 10% was observed ( the first team had 10% more wins than the second). The coach observer reports two- sample t-test shows this difference is statistically significant. How would you interpret these findings? What questions or concerns would you have? How might this type of study be improved? Hint: Consider the possibility that the test performed was not the appropriate one.
Investigation 3.2: Valence Differences Between R&B and Rap Genres (Paired)A music fan claims that R&B songs tend to have a more positive tone on average than do Rapsongs. The individual collected two independent random samples from the population of SpotifySongs. Fifteen R&B songs and another fifteen Rap songs were collected and their Valence wasrecorded. The music fan believed that pairing the song by their Danceability may provideadditional information. Danceability describes how suitable a track is for dancing based on acombination of musical elements including tempo, rhythm stability, beat strength, and overallregularity. A value of 0.0 is least danceable and 1 is most danceable. Thus, the individual pairedthe R&B song with the lowest danceability with the Rap song with the lowest danceability,followed by the second and second, third and third. She continued this process until the R&Bsong with the highest danceability was paired with the Rap song with the…
Suppose that, as part of a research methods class, Bailey was asked to write a summary of a research paper on the topic of the effects of visitor traffic on the relative humidity in bat caves. Identify the explanatory and the response variables. The number of visitors and the relative humidity are the response variables. The number of visitors is the response variable, and the relative humidity is the explanatory variable. The number of visitors and the relative humidity are the explanatory variables. The number of visitors is the explanatory variable, and the relative humidity is the response variable.
Indicate whether 25 is sufficient or whether a sample of 50 would be necessary. You will want to calculate the probability of the sample mean being between $11,000 and $13,000 for both a sample size of 25 and 50. (Thank You!)
A doctor wanted to study the effect of four different treatments on mental health. A group of 100 adults experiencing depression volunteered for the study. The doctor randomly assigned one-fourth of them to each of four groups. Group 1 followed a specific exercise plan, group 2 followed a specific diet plan, group 3 followed an exercise and diet plan, and group 4 did not follow any plan. After 4 weeks, the doctor contacted each participant and asked them if they felt any better. The results are displayed in the table. The doctor would like to know if these data provide convincing evidence that the distribution of responses differs across the treatment groups in the population of all patients like these. The random condition is met. The 10% condition is not needed because random sampling did not take place. This table of expected counts shows that all expected counts are at least 5. What is the value of the chi-square test statistic? χ‑2 = 5.03 χ‑2 = 6.26 χ‑2 = 25.33 χ‑2 = 39.22