The data table contains waiting times of customers at a bank, where customers enter a single waiting line that feeds three teller windows. Test the claim that the standard deviation of waiting times is less than 2.3 minutes, which is the standard deviation ofwaiting times at the same bank when separate waiting lines are used at each teller window. Use a significance level of 0.025. Complete parts (a) through (d) below.E Click on the icon to view the data.a. Identify the null and alternative hypotheses. Choose the correct answer below.O A. Ho: 0 = 2.3 minutesO B. Ho: o<2.3 minutesHA: 0= 2.3 minutesHA: 0+ 2.3 minutesO C. Ho: o= 2.3 minutesO D. Ho: 02 2.3 minutesHA: o< 2.3 minutesHA: o<2.3 minutesb. Compute the test statistic.(Round to two decimal places as needed.)c. Find the P-value of the test statistic.The P-value of the test statistic is(Round to three decimal places as needed.)d. Does the use of the single line appear to reduce the variation among waiting times?Therev sufficient evidence to conclude that the single line reduced the variation among waiting times because Ho isvby the hypothesis test. Customer Waiting TimesCustomer Waiting Times(in minutes)6.66.46.47.37.46.67.77.37.26.96.37.46.76.912.86.67.47.514.57.36.37.46.611.87.86.56.37.86.87.57.47.57.714.87.68.27.56.78.87.76.86.713.87.17.86.78.96.24.27.56.17.66.76.46.87.77.36.26.27.3

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Answered: The data table contains waiting times…

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter7: Percents

Section7.2: Percents And Proportions

Problem 18E

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Online Trailer Views (millions) Opening Weekend Box Office Gross ($millions) Online Trailer Views (millions) Opening Weekend Box Office Gross ($millions) 58.485 31.963 3.169 1.611 10.539 2.563 32.824 63.843 7.290 6.615 4.267 13.376 11.117 20.214 42.382 86.251 83.747 102.996 4.989 4.690 32.036 60.081 6.630 33.377 21.858 19.098 0.942 3.705 6.362 9.752 2.258 1.513 1.984 9.872 11.327 18.470 47.499 35.661 8.966 12.202 5.433 21.575 15.177 4.357 27.396 18.002 13.714 30.436 2.141 2.859 31.231 53.003 57.337 150.198 52.612 46.607 7.918 11.225 16.235 13.003 8.372 6.775 6.884 3.776 9.117 0.427 11.698 18.223 1.888 5.706 2.827 3.471 2.883 3.998 23.075…
Regional Gross Worldwide Gross First Title Weekend 1. 91.644 317.316 976.556 2. 88.889 263.436 895.633 3. 92.224 245.627 789.697 104.239 287.545 886.763 77.141 296.271 921.237 78.032 304.116 930.925 Print Done
Course Eval Prof Eval4.0 4.64.5 4.74.0 3.94.3 4.74.3 4.94.3 4.63.9 4.63.3 3.14.7 5.04.1 3.93.1 3.44.1 4.34.0 4.33.2 3.62.7 3.14.6 4.33.7 4.74.1 4.04.5 4.73.4 3.63.4 3.53.3 3.34.4 4.44.5 4.34.1 4.54.5 4.64.2 4.74.0 4.33.5 3.84.3 4.42.4 2.23.6 4.34.7 4.74.0 4.14.2 3.94.4 4.14.0 4.14.0 3.94.1 4.04.8 4.83.4 3.14.5 4.53.4 3.23.9 3.84.6 4.34.7 4.93.3 3.93.7 4.04.0 4.54.1 4.24.2 4.34.0 4.04.5 4.83.7 4.43.2 3.53.5 3.93.9 3.94.3 4.03.1 3.63.2 3.24.1 4.44.1 4.53.4 3.93.6 3.94.5 4.33.7 3.64.1 4.62.2 2.12.7 3.34.1 4.73.3 3.54.5 4.83.4 4.23.5 4.13.7 3.84.2 4.53.8 4.64.2 4.33.7 4.04.9 5.13.7 3.43.5 3.43.5 4.34.7 4.84.6 5.04.1 4.73.0 3.43.4 3.53.5 3.84.1 4.23.9 3.94.3 4.43.4 3.3
Customer Waiting Times (in minutes) 8.4 6.8 6.4 7.6 6.2 6.4 6.9 6.3 6.3 6.4 8.3 7.3 6.7 7.7 7.3 7.2 6.8 7.5 10.4 6.3 7.6 7.8 7.7 12.6 7.2 8.3 6.7 7.3 7.5 6.7 6.1 6.3 8.2 5.3 7.8 7.8 7.3 6.4 7.2 7.7 8.4 7.6 14.8 6.3 6.7 7.3 8.1 7.9 8.9 7.5 7.6 7.7 6.8 6.2 7.1 6.9 8.4 8.4 6.8 6.1
2) Explain your independent and dependent variables 3) Tell your initial expected finding on the relationship between them and give your rationale behind your feelings 4) What is your population 5) Develop a survey including other variables like grade level (freshman/sophomore/junior/senior), major, marriage status (single/married/widowed/divorced) etc 5) Explain how you obtained your sample.. If it was convenience- discuss what would have been a better way to get the sample
Suppose that 7.3, 6.1, 3.8, 8.4, 6.9, 7.1, 5.3, 8.2, 4.9, and 5.8 are ten observations from a normal distribution with unknown mean and unknown variance. What is the half width for the 95% confidence interval for the population mean? (Hint: refer to page 36.) Here is a t table that contains what you will need (and more).
Customer Day Mon Browser Time (min) Pages Viewed Amount Spent ($) 1 Chrome 12.0 4 54.52 2 Wed Other 19.5 94.90 3 Mon Chrome 8.5 4 26.68 4 Tue Firefox 11.4 2 44.73 Chrome Firefox Wed 11.3 4 66.27 Sat 10.5 67.80 7 Sun Chrome 11.4 36.04 8 Fri Firefox 4.3 55.96 9 Wed Firefox 12.7 3 70.94 10 Tue Chrome 24.7 7 68.73 11 Sat Other 13.3 6. 54.04 12 Sun Firefox 14.3 48.05 13 Sun Other 11.7 7 64.16 14 Mon Firefox 24.4 10 158.51 15 Fri Chrome 8.4 3 84.12 16 Thu Chrome 9.6 4 59.20 17 Thu Chrome 23.3 7 91.62 18 Mon Chrome 14.0 126.40 19 Fri Other 5.6 4 68.45 20 Wed Chrome 15.1 5 32.69 21 Sat Firefox 16.3 5 78.58 22 Tue Chrome 10.2 6. 74.43 23 Sun Chrome 8.0 3 32.73 24 Tue Firefox 8.0 2 48.66 25 Fri Firefox 9.6 3 54.66 26 Wed Chrome 11.0 40.54 27 Sat Chrome 16.9 5 34.69 28 Sat Firefox 6.0 4 27.91 29 Fri Firefox 32.9 10 155.30 30 Mon Other 11.8 9 120.25 31 Thu Chrome 7.1 41.20 32 Fri Firefox 18.0 8 134.40 33 Sun Chrome 11.8 37.17 34 Fri Chrome 9.1 3 52.09 71.81 59.99 35 Tue Chrome 7.8 5 36 Mon Firefox…
The new management at a bakery claims that workers are now more productive than they were under old management, which is why wages have “generally increased." Let W be Worker i's wage under the old management and let W be Worker i's wage after the change. The difference is D, = W – W. Assume that the D, are a random sample from a Normal (µ, o²) distribution. |(i) Using the following data on 15 workers, construct an exact 95% confidence interval for u. (ii) Formally state the null hypothesis that there has been no change in average wages. In particular, what is E(D,) under H,? If you are hired to examine the validity of the new management's claim, what is the relevant alternative hypothesis in terms of µ = E(D,)? |(iii) Test the null hypothesis from part (ii) against the stated alternative at the 5% and 1% levels. |(iv) Obtain the p-value for the test in part (iii).
Median Household Income ($) % of population over 25 with BA degree and higher 100,929 42.1 71,348 20.5 59,961 25.0 69,588 21.1 108,689 39.4 90,996 32.1 63,284 19.5 53,746 27.5 58,528 13.4 66,834 15.2 63,647 12.5 49,757 16.2 82,439 29.9 60,980 13.5 136,032 54.8 55,057 22.5 59,460 13.0 74,320 23.1 92,291 31.9 72,723 32.8 101,991 37.3 96,623 35.7…
The distribution of course grades in a very large class is (approximately) Normal with mean 48 and standard deviation 14. The minimum possible grade is 0 and the maximum possible grade is 120. A grade of 90 or more is required to get "A+". The course instructor is considering the possibility of a "bell curve" that will increase the mean grade to 77 and decrease the standard deviation to 6. What is the proportion of students that will get "A+" if the bell curve is applied?
1162,1116,1283,1277,1364,1322,1297,1206,1135,1316,1076,1172,1316,1212,1339,1199,1252,1125,1314,1306,1209 Price of Laptop Computers (in Dollars) Class Frequency Relative Frequency Cumulative Frequency 1073–1122 1123–1172 1173–1222 1223–1272 1273–1322 1323–1372 Step 1 of 4 : Determine the class width of the classes listed in the frequency table.

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