The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the bestpredicted weight of a bear with a chest size of 50 inches. Is the result close to the actual weight of 407 pounds? Use a significance level of 0.05.4549 51 53 61 57368 382 420 481 457 287Chest size (inches)Weight (pounds)Click the icon to view the critical values of the Pearson correlation coefficient r.(---)What is the best predicted weight of a bear with a chest size of 50 inches?The best predicted weight for a bear with a chest size of 50 inches is pounds.(Round to one decimal place as needed.) The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the bestpredicted weight of a bear with a chest size of 50 inches. Is the result close to the actual weight of 407 pounds? Use a significance level of 0.05.Chest size (inches)Weight (pounds)Click the icon to view the critical values of the Pearson correlation coefficient r.5361574549 51368 382 420 481 457 287What is the regression equation?y=+x (Round to one decimal place as needed.)CERE

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Answered: The data show the chest size and weight…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Recently, the stock market took big swings up and down. A survey of 969 adult investors asked how often they tracked their portfolio. The table shows the investor responses. What is the probability that an adult investor tracks his or her portfolio weekly? Express your answer as a simplified fraction and as a decimal rounded to three decimal places. How frequently? Response Daily O 231 269 274 Couple times a year 143 Don't track 52 Weekly Monthly 274 969 231 969 269 969 143 969 ;0.283 ;0.238 ;0.278 ;0.148
Find the equation of the regression line for the given data. Then construct a scatter plot of the data and draw the regression line. (The pair of variables have a significant correlation.) Then use the regression equation to predict the value of y for each of the given x-values, if meaningful. The table below shows the heights (in feet) and the number of stories of six notable buildings in a city. Height, x Stories, y 758 621 518 510 492 | 483 | 51 47 46 43 39 36 Find the regression equation. y = ☐ X+ (a) x = 503 feet (c) x = 802 feet (b) x = 649 feet (d) x = 728 feet (Round the slope to three decimal places as needed. Round the y-intercept to two decimal places as needed.)
he data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 51 inches. Is the result close to the actual weight of 4 punds? Use a significance level of 0.05. thest size (inches) Veight (pounds) Click the icon to view the critical values of the Pearson correlation coefficient r. 45 43 43 52 52 352 374 275 314 440 367 Critical Values of the Pearson Correlation Coefficient r What is the regression equation? Critical Values of the Pearson Correlation Coefficient r a = 0.05 NOTE: To test Ho: p=0 against H, p#0, reject Ho if the absolute value of r is greater than the critical value in the table. y%3= x (Round to one decimal place as needed.) a = 0.01 4 0.950 0.990 0.878 0.959 0.811 0.917 0.754 0.875 8. 0.707 0.834 9. 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.606 0.590…
The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 41 inches. Is the result close to the actual weight of 153 pounds? Use a significance level of 0.05. Chest size (inches) Weight (pounds) Click the icon to view the critical values of the Pearson correlation coefficient r. 40 53 38 43 44 58 D 227 360 153 206 234 414 What is the regression equation? y=+x (Round to one decimal place as needed.) What is the best predicted weight of a bear with a chest size of 41 inches? The best predicted weight for a bear with a chest size of 41 inches is (Round to one decimal place as needed.) Is the result close to the actual weight of 153 pounds? O A. This result is exactly the same as the actual weight of the bear. O B. This result is close to the actual weight of the bear. O C. This result is very close to the actual weight of the bear. O D. This…
The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 40 inches. Is the result close to the actual weight of 392 pounds? Use a significance level of 0.05. Chest size (inches) Weight (pounds) E Click the icon to view the critical values of the Pearson correlation coefficient r. 41 54 44 55 39 51 328 528 418 580 296 503 ..... What is the regression equation? y =+x (Round to one decimal place as needed.) What is the best predicted weight of a bear with a chest size of 40 inches? The best predicted weight for a bear with a chest size of 40 inches is pounds. (Round to one decimal place as needed.) Is the result close to the actual weight of 392 pounds? O A. This result is close to the actual weight of the bear. O B. This result is exactly the same as the actual weight of the bear. O C. This result is very close to the actual weight of the…
Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported asy=43.25x+19.44y=43.25x+19.44and the r=0.98r=0.98.What proportion of the variation in y can be explained by the variation in the values of x?r² = %
help
The paired data below consists of heights and weights of 6 randomly selected adults. Find the linear correlation coefficient, the linear regression line, and predict the weight of a randomly selected person who is 1.69 meters tall. X Height (meters) 1.61 1.72 1.78 1.80 1.67 1.88 Y Weight (kg) 54 62 70 84 61 92
find t reject or fail to reject
Prev The table below gives the age and bone density for five randomly selected women. Using this data, consider the equation of the regression line, y = bo + b₁x, for predicting a woman's bone density based on her age. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, In practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant. Age Bone Density 61 62 68 69 40 357 350 343 340 315 Step 1 of 6: Find the estimated slope. Round your answer to three decimal places. Table Copy Data Next
The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 48 inches. Is the result close to the actual weight of 308 pounds? Use a significance level of 0.05. Chest size (inches) Weight (pounds) Click the icon to view the critical values of the Pearson correlation coefficient r. 58 49 58 43 46 57 355 266 332 177 246 348 What is the regression equation? y = + x (Round to one decimal place as needed.) %3D What is the best predicted weight of a bear with a chest size of 48 inches? The best predicted weight for a bear with a chest size of 48 inches is pounds. (Round to one decimal place as needed.) Is the result close to the actual weight of 308 pounds? A. This result is not very close to the actual weight of the bear. B. This result is close to the actual weight of the bear. C. This result is exactly the same as the actual weight of the bear.…

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