The data set below shows the amount of trash generated by ten households (in pounds per day). Assume that the population is normally distributed. 3:9 4:6 15:6 10:5 16:0 6:7 12:0 9:2 13:8 16:8 (a) Construct a 95% confidence interval for the mean based on the sample. (b) Construct a 90% confidence interval for the mean. (c) Construct an 80% confidence interval for the mean.
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NEW Q4
The data set below shows the amount of trash generated by ten households (in pounds per day). Assume that the population is
3:9 4:6 15:6 10:5 16:0 6:7 12:0 9:2 13:8 16:8
(a) Construct a 95% confidence interval for the
(b) Construct a 90% confidence interval for the mean.
(c) Construct an 80% confidence interval for the mean.
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- Library A food safety guideline is that the mercury in fish should be below 1 part per million (ppm). Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 90% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna sushi? 0.58 0.74 0.10 0.92 1.32 0.49 0.96 t: 0 What is the confidence interval estimate of the population mean p? ppmYou are interested in finding a 95% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 13 randomly selected college students. Round answers to 3 decimal places where possible. 4 11 11 7 10 7 9 2 8 11 9 4 12 a. To compute the confidence interval use a distribution. b. With 95% confidence the population mean number of days of class that college students miss is between and days. c. If many groups of 13 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of missed class days and about percent will not contain the true population mean number of missed class days.Question Help v The data below shows the sugar content in grams of several brands of children's and adults' cereals. Create and interpret a 95% confidence interval for the difference in the mean sugar content, uC-HA. Be sure to check the necessary assumptions and conditions. (Note: Do not assume that the variances of the two data sets are equal.) Full data set Children's cereal: 43.3, 56.1, 49.6, 42.2, 54, 47.6, 54.1, 42.9, 42.2, 43, 48.7, 40.4, 37.5, 57.6, 49.4, 50.5, 38.3, 57.1, 40.6, 32 Adults' cereal: 21.5, 28.5, 0.1, 6.1, 4.2, 24.8, 15.4, 12.5, 20.9, 8.3, 7.5, 11.2, 15.9, 11.5, 0.1, 16.9, 0.7, 0.2, 1.5, 6.4, 13.8, The confidence interval is ). (Round to two decimal places as needed.) Enter your answer in the edit fields and then click Check Answer. 1 1 part remaining Clear AllYou are interested in finding a 90% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 14 randomly selected non-residential college students. Round answers to 3 decimal places where possible. 5 8 11 10 12 19 24 6 26 10 26 10 26 15 a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean commute for non-residential college students is between and miles. c. If many groups of 14 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of commute miles and about percent will not contain the true population mean number of commute miles.You are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 12 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 7 26 5 10 23 14 14 8 19 6 8 12 a. To compute the confidence interval use a ? z or t distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between __and ___visits. c. If many groups of 12 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About __percent of these confidence intervals will contain the true population mean number of visits per patient and about __percent will not contain the true population mean number of visits per patient.You are interested in finding a 98% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 14 randomly selected college students. Round answers to 3 decimal places where possible. 12 5 7 4 6 9 11 11 9 8 5 9 10 11 a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean number of days of class that college students miss is between and days. c. If many groups of 14 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of missed class days and about percent will not contain the true population mean number of missedFast reactions: In a study of reaction times, the time to respond to a visual stimulus x and the time to respond to an auditory stimulus y were recorded for each of 8 subjects. Times were measured in thousandths of a second. The results are presented in the following table. The results are presented in the following table. Visual Auditory 161 159 176 163 178 201 188 193 191 169 211 189 235 241 228 209 Construct a 95% confidence interval for the slope. Round the answers to at least four decimal places.You are interested in finding a 95% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 12 randomly selected college students. Round answers to 3 decimal places where possible. 10 12 6 12 11 7 6 4 12 8 12 7 a. To compute the confidence interval use a distribution. b. With 95% confidence the population mean number of days of class that college students miss is between and days. c. If many groups of 12 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of missed class days and about percent will not contain the true population mean number of missed class days.4.753, 4.375, 4.177, 4.677, 4.425, 4.227, 4.122, 4.250, 3.953, 4.195, 4.293, 4.413 An 80% confidence interval for the mean rate isPLEASE ELABORATE MORE The data set below shows the amount of trash generated by ten households (in pounds per day). Assume that the population is normally distributed. 3:9 4:6 15:6 10:5 16:0 6:7 12:0 9:2 13:8 16:8 (a) Construct a 95% confidence interval for the mean based on the sample. (b) Construct a 90% confidence interval for the mean. (c) Construct an 80% confidence interval for the mean.Sleeping outlier: A simple random sample of ten college freshmen were asked how many hours of sleep they typically got per night. The results were 24, 8, 6.5, 6, 9, 8.5, 7.5, 6.5, 8.5, 9.5 The data contain an outlier that is clearly a mistake. Eliminate the outlier, then construct a 95% confidence interval for the mean amount of sleep from the remaining values. A 95% confidence interval for the mean amount of sleep from the remaining values is ___ < u < ___.You are interested in finding a 90% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 15 randomly selected college students. Round answers to 3 decimal places where possible. 6 9 10 7 6 5 1 9 2 3 2 1 2 8 6 a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean number of days of class that college students miss is between and days. c. If many groups of 15 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of missed class days and about percent will not contain the true population mean number of missed class days.SEE MORE QUESTIONS