Get an education: In 2012 the General Social Survey asked 835 adults how many years of education they had. The sample meanwas 9.74 years with a standard deviation of 9.02 years.Part: 0 / 2Part 1 of 2(a) Construct a 99.8 % confidence interval for the mean number of years of education. Round the answers to at least twodecimal places.A 99.8 % confidence interval for the mean number of years of education is

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Answered: Get an education: In 2012 the General…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A survey of 50 young professionals found that they spent an average of $24.15w hen dining out, with a standard deviation of $12.06. Can you conclude statistically that the population mean is greater than $27? Use a 95% confidence interval is. The 95% confidence interval is _____ , _______As $27 is__________ of the confidence interval, we________ , conclude that the population mean is greater than $27. (Use ascending order. Round to four decimal places as needed.)
A test of writing ability is given to a random sample of 11 students before and after they completed a formal writing course. The results are given below: Before: Mean = 80.27, standard deviation = 12.76 After: Mean = 78.27, standard deviation = 12.92 Before/After: Mean = 2, standard deviation = 2.65 Construct a 99% confidence interval for the mean differencebetween the before and after scores. Round your answer to 3 decimal places.
In a survey, 23 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $47 and standard deviation of $9. Construct a confidence interval at a 80% confidence level.Give your answers to one decimal place.________ ± ________Interpret your confidence interval in the context of this problem.
a survey, 30 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $47 and standard deviation of $6. Construct a confidence interval at a 80% confidence level. Give your answers to one decimal place. H
Question Help A large family-held department store had the business objective of improving its response to complaints. The variable of interest was defined as the number of days between when the complaint was made and when it was resolved. Data were collected from 40 complaints that were made in the last year. Use the data to complete parts (a) through (d) below. E Click the icon to view the data table. a. Construct a 99% confidence interval estimate for the population mean number of days between the receipt of a complaint and the resolution of the complaint. The 99% confidence interval estimate is from days to days (Round to one decimal place as needed.) A Complaint Data Days Between Complaint and Resolution of Complaint 35 26 36 101 30 83 1 19 5 20 29 7 151 39 22 10 28 10 144 52 36 106 9. 8 17 27 29 86 85 20 16 85 10 21 ar 29 10 Enter your answer in the edit fields and then click Check Answer 38 12 37 31 ? 3 parts remaininc Print Done
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Get an education: The general social survey asked 1972 adults how many years of education they had. The sample mean was 13.37 years with a standard deviation of 3.13 years. a. Construct a 98% confidence interval for the mean number of years of education. b. Data collected in an earlier study suggests that the mean ten years ago was 13.26 years. A sosciologist believes that the mean now is the same. Does the confidence interval contradict this belief? Explain.
Active Learning vs Passive Learning: Feelings of Learning? After the active learning or passive learning class, students rated the extent to which they agreed with the statement “I feel like I learned a great deal from this class.” Ratings were on a 5-point scale with greater numbers indicating greater agreement. For the 142 students in the active learning environment, the mean rating was 3.338 with a standard deviation of 0.922. For the 154 students in the passive learning lecture, the mean rating was 3.753 with a standard deviation of 0.873. Test whether ratings on feelings of learning are significantly lower, on average, with active learning. (Let Group 1 represent active learning and Group 2 represent passive learning.)
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Salaries of 25 college graduates who took a statistics course in college have a mean of $79,350 and a standard deviation of $1,280. Construct a 98% confidence interval for estimating the population standard deviation. Enter the upper bound of the confidence interval. (Round your answer to nearest whole dollar.)
A researcher is interested in finding a 90% confidence interval for the mean number of times per day that college students text. The study included 149 students who averaged 34.2 texts per day. The standard deviation was 18.6 texts. Round to 3 decimals. b. With 90% confidence the population mean number of texts per day is between _______ and ________ texts a day.
Question: Part B. Construct a 95% confidence interval of the mean pulse rate for adult males. __bpm <u<__bpm Multiple Choice: Compare the results. A. The confidence intervals do not overlap, so it appears that adult females have a significantly higher mean pulse rate than adult males. B. The confidence intervals overlap, so it appears that adult males have a significantly higher mean pulse rate than adult females. C. The confidence intervals do not overlap, so it appears that there is no significant difference in mean pulse rates between adult females and adult males. D. The confidence intervals overlap, so it appears that there is no significant difference in mean pulse rates between adult females and adult males.

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