The current in the figure below is 0.72 A. (Let the internal resistance of battery 1 be  r1 = 1.2 Ω  and the internal resistance of battery 2 be  r2 = 1.2 Ω.)   (a) Find the voltage drop Vab.  1.272 V (b) Find the power dissipated in R.  0.9158 W   (c) Find the useful electric power supplied by battery 2. (Note: Do not forget the internal resistance of battery 2.)  5.857 W

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