The cumene process is used to convert benzene and propene in the presence of oxygen to phenol and acetone via the reaction CH+C3H6+0₂ CH₂OH + C₂H₂O This reaction is carried out with excess benzene and excess oxygen to ensure that no side reactions occur. A 1.16 ratio of benzene to propene is fed to a reactor in the presence of 35.0% excess air (N₂ and O₂). The first pass conversion of propene is 100%. The products leave the reactor and enter a condenser where the gaseous nitrogen and oxygen leave the process and the liquid organic products are fed to a distillation column. The distillation column separates the products from the reactants. Any unreacted reactants are fed into the fresh feed stream. The products are directed to a second distillation column that separates th acetone from the phenol. If 11.8 kg/hr of phenol is produced from this process, answer each of the questions. First, label the process flow diagram, putting either a given numeric value or the words "unknown" or "none" in each space. Do not leave any spaces blank. Variable names are shown for reference later. Fresh feed n₁= x₁= mol/hr mol CH/mol Reactor feed n₂= x= mol/hr mol CH /mol X₁ = Reactor n3= n X11 X12 mol/hr n= mol/hr mol C H/mol mol C₂H/mol Condenser mol gas/hr n= mol/hr Distillation column 1