The crystalline lens of the human eye is a double-convex lens made of material having an index ofrefraction of 1.44 (although this varies). Its focallength in air is about 8.00 mm, which also varies.We shall assume that the radii of curvature of itstwo surfaces have the same magnitude.(Note: The results obtained in the parts A, B and Care not strictly accurate, because the lens isembedded in fluids having refractive indexesdifferent from that of air.)Find the radii of curvature of this lens.R =ΜΕ ΑΣΦSubmitRequest AnswerPart B?mmIf an object 10.0 cm tall is placed 33.0 cm from the eye lens, where would the lens focus it?ΜΕ ΑΣΦ?s' =SubmitRequest AnswerPart CHow tall would the image be?Π ΑΣΦ3=SubmitRequest Answer?mmmm

The objective of this question is to find the radii of curvature of the human eye lens and to…

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The crystalline lens of the human eye is a double-convex lens made of material having an index of refraction of 1.44 (although this varies). Its focal length in air is about 8.00 mm, which also varies. We shall assume that the radil of curvature of its two surfaces have the same magnitude. (Note: The results obtained in the parts A, B and C are not strictly accurate, because the lens is embedded in fluids having refractive indexes different from that of air.) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of The eye's lens. Part A Find the radii of curvature of this lens. Express your answer in millimeters. R= 7.0 mm Submit ✓ Correct Set Up: = (n − 1)(-). If R is the radius of the lens, then R₁ = R and R₂=-R₁ ² + ² = }· m = ² = -² Solve: = (n − 1) (₁ - ₁) = (n − 1) ( ²2 - ) = ²(n-¹) R=2(n-1)f=2(1.44) (8.00mm) = 7.04mm Part B If an object 12.0 cm tall is placed 26.0 cm from the eye lens, where would the lens focus it? Express your answer in…
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