The crystalline lens of the human eye is a double-convex lens made of material having an index of refraction of 1.44 (although this varies). Its focal length in air is about 8.00mm, which also varies. We shall assume that the radil of curvature of its two surfaces have the same magnitude.(Note: The results obtained in the parts A, B and C are not strictly accurate, because the lens is embedded in fluids having refractive indexes different from that of air.)For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of The eye's lens.Part AFind the radii of curvature of this lens.Express your answer in millimeters.R= 7.0 mmSubmit✓ CorrectSet Up: = (n − 1)(-). If R is the radius of the lens, then R₁ = R and R₂=-R₁ ² + ² = }·m = ² = -²Solve: = (n − 1) (₁ - ₁) = (n − 1) ( ²2 - ) = ²(n-¹)R=2(n-1)f=2(1.44) (8.00mm) = 7.04mmPart BIf an object 12.0 cm tall is placed 26.0 cm from the eye lens, where would the lens focus it?Express your answer in millimeters.ΓΆΠΤΑΣΦSubmitPart CHow tall would the image be?Express your answer in millimeters.SubmitPart DPrevious AnswersⒸrealO virtualSubmit[ΠΑΣΦIs this image real or virtual?Part ERequest AnswerRequest Answer✓ CorrecterectⒸinvertedPrevious Answers8>0 so the image is real.Is it erect or inverted?Submit Previous Answers✓ Correct→O [20 "?Ć 62 "?mmmm.m< 0 so the image is inverted.Reflect: The lens is converging and has a very short focal length. As long as the object is farther than 7.0 mm from the eye, the lens forms a real image.

n=1.44f=8.00 mm=0.8 cms=26 cmhi=12 cm

Answered: The crystalline lens of the human eye…

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