The contingency table shows how a random sample of adults rated a newly released movieand their age group. At a-0.05, can you conclude that the adult's ratings are related to age group?Age-group18-3031-50Above 50RatingExcellent Good97101158423337Fair262521Poor51119Terrible331510

The contingency table shows how a random sample of adults rated a newly released movie:-…

Answered: The contingency table shows how a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You play roulette and observe the ball land in the 1st dozen (i.e., 1-12) 5 times out of 5 spins. You want to perform a test to determine if the wheel is fair. State the null and alternative hypothesis. What is the p-value of this test? For ? α =.05 significance level, what do you conclude?
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The 2008 general social survey asked a nationally representative sample of 1324 adult americans to report how many hours of television they watch in a typical day. The resulting data are reported in the following table counts. What is the mean numbers of hours of tv watched?
Is there a relationship between Facebook use and age among college students? The following two-way table displays data for the 219 students who responded to the Age Younger (18–22) Middle (23–27) Older (28 and up) Facebook user? Yes 78 49 21 No 4 21 46 What percent of the students who responded were Facebook users? What percent of the students in the sample were aged 28 or older? What percent of the students who responded were older Facebook users? What percent of the Facebook users in the sample were younger students? Find the distribution of Facebook use for each of the three age groups. Make a stacked bar graph to compare these Describe what the graph in part (e) reveals about the association between age and Facebook
An instructor in a statistics course set a final exami- nation and also required the students to do a data analysis project. For a random sample of 10 students, the scores obtained are shown in the table. Find the sample correlation between the examination and proj- ect scores. Examination 81 62 74 78 93 69 72 83 90 84 Project 76 71 69 76 87 62 80 75 92 79
A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 37 46 59 83 225 No 213 204 191 167 775 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
Foxbees magazine published data on the best small firms in 2012. These publicly traded firms have a stock price of at least $5 per share and have reported annual revenue between $5 million and $1 billion. The data below shows the ages of the corporate CEOS for a random sample of these firms. 49 67 59 48 45 49 39 44 37 38 48 38 43 48 62 74 70 58 58 40 74 35 36 54 38 45 54 55 64 75 69 36 55 72 69 60 40 64 39 59 74 52 40 49 38 38 74 50 55 50 R vector Copy to clipboard a) What is the mean of the sample? (Round to 4 decimal places) b) What is the standard deviation of the sample mean or the standard error? (Round to 4 decimal places) c) What is the sample size? (Round to whole number)
Is there an association between hair color and body type? The table below shows the results of a researcher's observations of randomly selected people. Frequencies of Hair Colors for Various Body Types Blonde Brunette Red Head 71 80 96 108 55 115 46 91 Short and Slender Short and Pudgy Tall and Slender Tall and Heavy What can be concluded at the o= 0.01 significance level? 53 74 69 63
Please answer the following question using *********EXCEL*******
Texting while driving has become a national focus now that cell phones are ubiquitous and texting while driving results in ever-increasing injuries and deaths. According to 2013 study, 44.5% of US Teenage drivers text while driving. You want to see how Gainesville teenage drivers compare to national teens. You randomly select 300 local high school students (ages 16-19) and ask if they have texted while driving within the past 30 days. The data is recorded in the table. Yes No 142 158 Find a 95% confidence interval for the percentage of teenage drivers who text while driving. Then explain what the confidence interval means in this context.

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