The concentration of the complex ion in each of following solutions is 1.00 M. In which of the solutions will the concentration ol the uncomplexed metal ion be the lowest? Be(OH) K 40 1018 Zn(OH), K 3.0 1015 Cu(NH) K 56 1011 Cdl K= 1.0x 10 Hg Ca Zn

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### Educational Content: Complex Ion Concentration in Solutions

#### Topic: Chemistry - Complex Ions and Equilibrium

**Problem Statement:**
The concentration of the complex ion in each of the following solutions is 1.00 M. In which of the solutions will the concentration of the uncomplexed metal ion be the lowest?

**Given Data:**

1. \( \text{Be(OH)}_4^{2-} \), \( K_f = 4.0 \times 10^{18} \)
2. \( \text{Zn(OH)}_4^{2-} \), \( K_f = 3.0 \times 10^{15} \)
3. \( \text{Cu(NH}_3\text{)}_4^{2+} \), \( K_f = 5.6 \times 10^{11} \)
4. \( \text{CdI}_4^{2-} \), \( K_f = 1.0 \times 10^6 \)

**Question:**
In which of the solutions will the concentration of the uncomplexed metal ion be the lowest?

**Choices:**

- \( \text{Cu}^{2+} \)
- \( \text{Hg}^{2+} \)
- \( \text{Cd}^{2+} \)
- \( \text{Be}^{2+} \)
- \( \text{Zn}^{2+} \)

**Explanation with Context:**

In coordination chemistry, the formation constant (\( K_f \)) of a complex ion indicates the stability of the complex in solution. A larger \( K_f \) value suggests a greater tendency of the metal ion to remain in the complex ion form, resulting in a lower concentration of free or uncomplexed metal ion.

**Detailed Analysis:**

1. **\( \text{Be(OH)}_4^{2-} \) with \( K_f = 4.0 \times 10^{18} \):**
   - Extremely high formation constant, implying \( \text{Be}^{2+} \) is mostly complexed.
   
2. **\( \text{Zn(OH)}_4^{2-} \) with \( K_f = 3.0 \times 10^{15} \):**
   - Still a high formation constant, but not as high as \( \text{Be(OH)}_4^{
Transcribed Image Text:### Educational Content: Complex Ion Concentration in Solutions #### Topic: Chemistry - Complex Ions and Equilibrium **Problem Statement:** The concentration of the complex ion in each of the following solutions is 1.00 M. In which of the solutions will the concentration of the uncomplexed metal ion be the lowest? **Given Data:** 1. \( \text{Be(OH)}_4^{2-} \), \( K_f = 4.0 \times 10^{18} \) 2. \( \text{Zn(OH)}_4^{2-} \), \( K_f = 3.0 \times 10^{15} \) 3. \( \text{Cu(NH}_3\text{)}_4^{2+} \), \( K_f = 5.6 \times 10^{11} \) 4. \( \text{CdI}_4^{2-} \), \( K_f = 1.0 \times 10^6 \) **Question:** In which of the solutions will the concentration of the uncomplexed metal ion be the lowest? **Choices:** - \( \text{Cu}^{2+} \) - \( \text{Hg}^{2+} \) - \( \text{Cd}^{2+} \) - \( \text{Be}^{2+} \) - \( \text{Zn}^{2+} \) **Explanation with Context:** In coordination chemistry, the formation constant (\( K_f \)) of a complex ion indicates the stability of the complex in solution. A larger \( K_f \) value suggests a greater tendency of the metal ion to remain in the complex ion form, resulting in a lower concentration of free or uncomplexed metal ion. **Detailed Analysis:** 1. **\( \text{Be(OH)}_4^{2-} \) with \( K_f = 4.0 \times 10^{18} \):** - Extremely high formation constant, implying \( \text{Be}^{2+} \) is mostly complexed. 2. **\( \text{Zn(OH)}_4^{2-} \) with \( K_f = 3.0 \times 10^{15} \):** - Still a high formation constant, but not as high as \( \text{Be(OH)}_4^{
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