The concentration of CO2 in air may be determined by an indirect acid-base titration. A sample of air is bubbled through a solution containing an excess of barium hydroxide, and the CO2 is removed by precipitation as it reacts with Ba(OH)2. 8. Ba(OH)2(aq) + CO2(g) → BaCO3(s)+H2O(1) Not all of the Ba(OH)2 reacts with CO2-some is left over. The mixture is filtered to remove solid BaCO3, the solid is rinsed, the filtrate and rinsings are combined, and the leftover Ba(OH)2 is titrated with HCl. Ва(ОН)2(аq) + 2 HС(ад) —> ВаСlz(ад) + 2 H-0() In a typical analysis, a 5.0-L sample of air was bubbled through 50.00 mL of 0.0320 M Ba(OH)2. Back titrating (that was a hint) with 0.0256 M HCl required 38.08 mL to reach the end point. Determine the concentration of CO2 (FM = 44.01) in the sample of air in units of mg/L.

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The concentration of CO2 in air may be determined by an indirect acid-base titration. A sample of air is
bubbled through a solution containing an excess of barium hydroxide, and the CO2 is removed by precipitation
as it reacts with Ba(OH)2.
8.
Ba(OH)2(aq) + CO2(g) → BaCO3(s)+H2O(1)
Not all of the Ba(OH)2 reacts with CO2-some is left over. The mixture is filtered to remove solid BaCO3, the
solid is rinsed, the filtrate and rinsings are combined, and the leftover Ba(OH)2 is titrated with HCl.
Ва(ОН)2(аq) + 2 HС(ад) —> ВаСlz(ад) + 2 H-0()
In a typical analysis, a 5.0-L sample of air was bubbled through 50.00 mL of 0.0320 M Ba(OH)2. Back titrating
(that was a hint) with 0.0256 M HCl required 38.08 mL to reach the end point. Determine the concentration of
CO2 (FM = 44.01) in the sample of air in units of mg/L.
Transcribed Image Text:The concentration of CO2 in air may be determined by an indirect acid-base titration. A sample of air is bubbled through a solution containing an excess of barium hydroxide, and the CO2 is removed by precipitation as it reacts with Ba(OH)2. 8. Ba(OH)2(aq) + CO2(g) → BaCO3(s)+H2O(1) Not all of the Ba(OH)2 reacts with CO2-some is left over. The mixture is filtered to remove solid BaCO3, the solid is rinsed, the filtrate and rinsings are combined, and the leftover Ba(OH)2 is titrated with HCl. Ва(ОН)2(аq) + 2 HС(ад) —> ВаСlz(ад) + 2 H-0() In a typical analysis, a 5.0-L sample of air was bubbled through 50.00 mL of 0.0320 M Ba(OH)2. Back titrating (that was a hint) with 0.0256 M HCl required 38.08 mL to reach the end point. Determine the concentration of CO2 (FM = 44.01) in the sample of air in units of mg/L.
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