The compound heptane, C7H16, is a good fuel. It is a liquid at ordinary temperatures. When the liquid is burned, the reaction involved is C7H16() +11 O₂(g) 7 CO₂(g) + 8 H₂O(g) The standard enthalpy of formation of liquid heptane at 25 °C is -224.2 kJ mol-¹; other relevant enthalpy of formation values in kJ mol-¹ are: C7H16(9) -187.6; CO₂(g) = -393.5; H₂O(g) = -241.8 (a) Calculate the enthalpy change in the burning of 4.000 mol liquid heptane to form gaseous products at 25°C. State explicitly whether the reaction is endothermic or exothermic. ΔΗ° = (b) Would more or less heat be evolved if gaseous heptane were burned under the same conditions? v What is the standard enthalpy change for vaporizing 4.000 mol C7H16() at 25°C? ΔΗ° = kJ KJ Calculate the enthalpy change in the burning of 4.000 mol gaseous heptane to form gaseous products at 25°C. ΔΗ° = kJ

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The compound heptane, C7H16, is a good fuel. It is a liquid at ordinary temperatures. When the liquid is burned, the reaction involved is
C7H16() +11 O₂(g) 7 CO₂(g) + 8 H₂O(g)
The standard enthalpy of formation of liquid heptane at 25 °C is -224.2 kJ mol-¹; other relevant enthalpy of formation values in kJ mol-¹ are:
C7H16(9) = -187.6; CO₂(g) = -393.5; H₂O(g) = -241.8
(a) Calculate the enthalpy change in the burning of 4.000 mol liquid heptane to form gaseous products at 25°C. State explicitly whether the reaction is
endothermic or exothermic.
ΔΗ° =
(b) Would more or less heat be evolved if gaseous heptane were burned under the same conditions?
What is the standard enthalpy change for vaporizing 4.000 mol C7H16(₂) at 25°C?
ΔΗ° =
kJ
Calculate the enthalpy change in the burning of 4.000 mol gaseous heptane to form gaseous products at 25°C.
AH° =
KJ
Transcribed Image Text:The compound heptane, C7H16, is a good fuel. It is a liquid at ordinary temperatures. When the liquid is burned, the reaction involved is C7H16() +11 O₂(g) 7 CO₂(g) + 8 H₂O(g) The standard enthalpy of formation of liquid heptane at 25 °C is -224.2 kJ mol-¹; other relevant enthalpy of formation values in kJ mol-¹ are: C7H16(9) = -187.6; CO₂(g) = -393.5; H₂O(g) = -241.8 (a) Calculate the enthalpy change in the burning of 4.000 mol liquid heptane to form gaseous products at 25°C. State explicitly whether the reaction is endothermic or exothermic. ΔΗ° = (b) Would more or less heat be evolved if gaseous heptane were burned under the same conditions? What is the standard enthalpy change for vaporizing 4.000 mol C7H16(₂) at 25°C? ΔΗ° = kJ Calculate the enthalpy change in the burning of 4.000 mol gaseous heptane to form gaseous products at 25°C. AH° = KJ
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