Two types of plastic are suitable for an electronics component manufacturer to use. The breaking strength of this plastic is important. It is known that σ1 = σ2 = 1.0 psi. From a random sample of size n1 = 10 and n2 = 12, the values x̄1 = 162.5 and x̄2 = 155.0 are obtained. The company will not adopt Plastic 1 unless its mean breaking strength exceeds that of Plastic 2 by at least 10 psi. The P-value for the test H0: µ1 - µ2 = 10 versus H1: µ1 - µ2 > 10 is closest to:

Given Data : For Sample 1 x̄1 = 162.5 σ1 = 1.0 n1 = 10 For Sample 2…

The company will not adopt Plastic 1 unless its mean breaking strength exceeds that of Plastic 2 by at least 10 psi. The P-value for the test H0: µ1 - µ2 = 10 versus H1: µ1 - µ2 > 10 is closest to:

The company will not adopt Plastic 1 unless its mean breaking strength exceeds that of Plastic 2 by at least 10 psi. The P-value for the test H0: µ1 - µ2 = 10 versus H1: µ1 - µ2 > 10 is closest to:

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

Two types of plastic are suitable for an electronics component manufacturer to use. The breaking strength of this plastic is important. It is known that σ₁ = σ₂ = 1.0 psi. From a random sample of size n₁ = 10 and n₂ = 12, the values x̄₁ = 162.5 and x̄₂ = 155.0 are obtained. The company will not adopt Plastic 1 unless its mean breaking strength exceeds that of Plastic 2 by at least 10 psi. The P-value for the test H₀: µ₁ - µ₂ = 10 versus H₁: µ₁ - µ₂ > 10 is closest to:

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