The communication link uses five different chips. The probability of error-free signal transmission is 0.75. In case of an error, the erasure probability is equal to 0.05, and if there is no erasure, then each of the signals is perceived with equal probability as any of the four other than it. Build a Reception Probability Table . The picture is an example of the step for the solution for the task below

A First Course in Probability (10th Edition)
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Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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 The communication link uses five different chips. The probability of error-free signal transmission is 0.75. In case of an error, the erasure probability is equal to 0.05, and if there is no erasure, then each of the signals is perceived with equal probability as any of the four other than it. Build a Reception Probability Table . The picture is an example of the step for the solution for the task below
Task 37: The communication link uses four different chips. The probability
of error-free signal transmission is 0.73. In the case of an error, the erasure
probability is 0.003, and if there is no erasure, then each of the signals is perceived
with equal probability as any of the three other than it. Build a reception
probability table.
Solution. If erasure has not occurred, then each of the signals at the
receiving end of the line will be accepted as any of the three, different from it with
a probability of (1-0.73-0.03)/3 = 0.08. Then,
0,73 0,08 0,08 0,08 0,003
0,08 0,73 0,08 0,08 0,003
0,08 0,08 0,73 0,08 0,003
0,08 0,08 0,08 0,73 0,003
Transcribed Image Text:Task 37: The communication link uses four different chips. The probability of error-free signal transmission is 0.73. In the case of an error, the erasure probability is 0.003, and if there is no erasure, then each of the signals is perceived with equal probability as any of the three other than it. Build a reception probability table. Solution. If erasure has not occurred, then each of the signals at the receiving end of the line will be accepted as any of the three, different from it with a probability of (1-0.73-0.03)/3 = 0.08. Then, 0,73 0,08 0,08 0,08 0,003 0,08 0,73 0,08 0,08 0,003 0,08 0,08 0,73 0,08 0,003 0,08 0,08 0,08 0,73 0,003
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