The common tangent CD of a reversed curve is 280.50 m and has an azimuth of 312-29. BC is a tangent of the first curve whose azimuth is 252*45'. DE is a tangent of the second curve whose azimuth is 218-13. The radius of the first curve is 180m. P.I. is at station 16+523.37. B is at P.C. and E is at P.T. What is the stationing of P..C.?

The common tangent CD of a reversed curve is 280.50 m and has an azimuth of 312-29. BC is a tangent of the first curve whose azimuth is 252*45'. DE is a tangent of the second curve whose azimuth is 218-13. The radius of the first curve is 180m. P.I. is at station 16+523.37. B is at P.C. and E is at P.T. What is the stationing of P..C.?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The common tangent CD of a reversed curve is 280.50 m and has an azimuth of 312-29. BC is a tangent of the first curve whose azimuth is 252*45'. DE is a
tangent of the second curve whose azimuth is 218-13. The radius of the first curve is 180m. P.I. is at station 16+523.37. B is at P.C. and E is at P.T. What is the
stationing of P.C.?

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