The combustion of propane is described by the chemical equation C3H8 (g) + 5O2(g) → 3CO₂(g) + 4H₂O(g) . If we have a partial pressure of 0.375 bar of propane as the reactant, what partial pressure of oxygen will we need to have a perfect amount to consume all of the propane with no unreacted propane or oxygen left over at the end of the reaction? 1.13 kPa 0.0750 bar 0 0.375 bar 1.88 bar

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The combustion of propane is described by the chemical equation
C3H8 (g) +502(g) → 3CO2(g) + 4H₂O(g)
. If we have a partial pressure of 0.375 bar of propane as the reactant, what partial
pressure of oxygen will we need to have a perfect amount to consume all of the
propane with no unreacted propane or oxygen left over at the end of the reaction?
1.13 kPa
0.0750 bar
0.375 bar
1.88 bar
Transcribed Image Text:The combustion of propane is described by the chemical equation C3H8 (g) +502(g) → 3CO2(g) + 4H₂O(g) . If we have a partial pressure of 0.375 bar of propane as the reactant, what partial pressure of oxygen will we need to have a perfect amount to consume all of the propane with no unreacted propane or oxygen left over at the end of the reaction? 1.13 kPa 0.0750 bar 0.375 bar 1.88 bar
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