The combustion of octane, C,H₁s. proceeds according to the reaction shown. 2C₂H₁ (1) +250₂(g) 16CO₂(g) + 18 H₂O(1) If 305 mol of octane combusts, what volume of carbon dioxide is produced at 19.0 °C and 0.995 atm? V = L

Q: Consider the following equation: NH 4NO 3 (s) --> N 2O (g) + 2H 2O (g) 100.0 g ammonium nitrate is…

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Q: Consider the following reaction:                           4 Al(s) + 3 O2(g)  → 2 Al2O3(s)…

A: Given, 2.00 L of pure oxygen at STP (0°C, 1 atm) to react completely with a certain sample of…

Q: The combustion of octane, C8H18 , proceeds according to the reaction shown. 2C8H18(I) + 25 O2…

A: The number of moles of carbon dioxide, produced in the reaction, is calculated as shown below where…

Q: The combustion of octane, C,H8, proceeds according to the reaction shown. 18' 2 C,H18(1) + 250,(g) –…

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Q: The combustion of octane, C, H, proceeds according to the reaetion shown. 18 2 C,H18() + 25 O,(g) →…

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Q: The combustion of octane, C,H18, proceeds according to the reaction shown. 2 C3H18(1) + 25 0,(g) –…

A: The balance chemical reaction :  2C8H18(L) + 25O2(g) ----> 16CO2(g) + 18H2O(L)  Number of moles…

Q: Consider the following unbalanced equation: C2H5OH(g) + O2(g) → CO2(g) + H2O(l) 1.55 g of ethanol…

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Q: Isooctane (C8H18) is the primary component of gasoline, which burns according to the reaction below.…

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Q: Oxygen gas reacts with powdered aluminum according to the reaction: Al(s) + O₂(g) → Al₂O3(s) What…

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Q: Ammonia, NH3, burns in oxygen gas according to the reaction: 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(l).…

A: Since oxygen gas is present in excess, ammonia is the limiting reagent in the given reaction. A…

Q: The combustion of octane, C,H2, proceeds according to the reaction shown. 18 2 C3H13(1) + 25 0,(g) -…

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Q: Assume methane is introduced to a reaction vessel that has a volume of 1.0L with a pressure of…

A: Number of moles of methane can be calculated as follows:…

Q: The combustion of octane, C,H,g, proceeds according to the reaction shown. 18 2CH18(1) + 25 O,(g) –…

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Q: 2Ag2O(s)》4Ag(s)+ O2(g) In this reaction, what mass of Ag2O(s)(in grams) is required to form 388 mL…

A: The combined relation between gas laws is known as the ideal gas law or the gas equation. The…

Q: The combustion of octane, C,H8, proceeds according to the reaction shown. 2C,H13(1) + 25 0,(g) → 16…

A: The equation for ideal gases holds relation among the variables P (pressure), n (moles), V (volume),…

Q: Ammonium nitrate, NH4NO3, can decompose explosively when heated to a high temperature according to…

A: Interpretation- To determine the how many liters of gaseous products would be formed. When NH4NO3,…

Q: The combustion of octane, Cg H18, proceeds according to the reaction shown. 2 C8H₁8 (1) + 25 O₂(g) →…

A: An ideal gas follows a theoretical concept in which there is no interparticle interaction between…

Q: The combustion of octane, Cg H₁8, proceeds according to the reaction shown. 2 Cg H₁g (1) + 25 O₂(g)…

A: Given: Moles of octane = 482 mol Temperature = 20.0oC Pressure = 0.995 atm

Q: Oxygen gas can be prepared by heating potassium chlorate according to the following equation…

A: The number of moles of oxygen is calculated as,

Q: 2NO-3(aq) + 5CO(g) + 2H+(aq) -> N2(g) + H2O(l) +5CO2(g)…

A: The given reaction is  2NO3-(aq) + 5CO(g) + 2H+(aq) → N2(g) + H2O(l) + 5CO2(g) ......(A)  Mass of…

Q: The combustion of octane, C, H,8. proceeds according to the reaction shown. 2C,H,,(1) + 250,(g) - 16…

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Q: Gaseous iodine pentafluoride, IF, can be prepared by the reaction of solid iodine and gaseous…

A: Given: Volume = 10 L Mass of I2 = 17 g Pressure of F2 = 2 atm

Q: Consider the following reaction: 2SO2(g) + O2(g)-> 2SO3(g) What is the theoretical yield of SO3 ? If…

A: Answer:The reactant that is exhausted first in the chemical reaction and decides the yield of…

Q: Consider the unbalanced chemical equation below: CaSiO3(s) + HF(g) → CaF2(aq) + SiF4(g) + H2O(l)…

A: Molar mass of CaSiO3 = 116.16 g/mol Therefore, moles of CaSiO3 reacted =  34.4 / 116.16 = 0.30 moles

Q: Rb2CO3 (s) + 2 HCe (aq) → 2 RbCe (aq) + H2O (e) + CO2 (g) When 69.3 g Rb,CO3 is allowed to react…

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Q: The combustion of octane, C,H,2, proceeds according to the reaction shown. 2C,H18() + 25 0,(g)16…

A: 2 moles of octane give 16 moles of CO2. So, 354 mol of octane will give (8*354) = 2832 mol of CO2.…

Q: The combustion of octane, C,H,8, proceeds according to the reaction shown. 2C,H,;(1) + 25 0, (g) →…

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Q: The combustion of octane, C,H8, proceeds according tỏ the reac 2 C3H18(1) + 25 0,(g) 16 CO, (g) + 18…

A: From the balanced equation: Number of moles of CO2 = 8 × number of moles of octane Ideal gas…

Q: Gaseous iodine pentafluoride, IFs, can be prepared by the reaction of solid iodine and gaseous…

A: We are given the following reaction:  I2(s)+5F2(g)------------>2IF5(g). The volume of flask, (V)…

Q: Liquid water can be decomposed into hydrogen and oxygen under suitable conditions (e.g.,…

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Q: methanol (CH3OH) can be synthesized by the reaction: CO (g) + H2 (g) = CH3OH (g). What volume, in…

A: Calculate the number of moles of methanol synthesizedMass of methanol = 35.7 gMolar mass of methanol…

Q: The combustion of octane, C,H 8, proceeds according to the reaction shown. 2 C,H18(1) + 25 0, (g) →…

A: Applying ideal gas equation PV = nRT  where P = pressure, V = volume ,T= Temp n= no.of moles , R=…

Q: What volume of water vapor would be produced from the combustion of 815.74 grams of propane (C3H8)…

A: Mass of propane (C3H8) = 815.74 g Mass of O2 = 1006.29 g Temparature = 350. degrees C Pressure =…

Q: The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l) + 25O2(g)…

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Q: Gaseous iodine pentafluoride, IF, can be prepared by the reaction of solid iodine and gaseous…

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Q: Combustion of hydrocarbons such as pentane (C5H12) produces carbon dioxide, a "greenhouse gas."…

A: Answer: Ideal Gas equation is shown below: PV=nRT Here: P=pressure of the gasV=volume of the…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.