The combustion of ammonia in the presence of excess oxygen yields NO2 and H20: 4 NH3 (g) + 7 02 (g) → 4 NO2 (g) + 6 H2O (g) The combustion of 174 g of ammonia consumes g of oxygen. Atomic weights: N=14.01, H=1.01, O=15.99. Input values only with 2 decimal places.
The combustion of ammonia in the presence of excess oxygen yields NO2 and H20: 4 NH3 (g) + 7 02 (g) → 4 NO2 (g) + 6 H2O (g) The combustion of 174 g of ammonia consumes g of oxygen. Atomic weights: N=14.01, H=1.01, O=15.99. Input values only with 2 decimal places.
Introductory Chemistry: A Foundation
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ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
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Chapter9: Chemical Quantities
Section: Chapter Questions
Problem 20CR
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![The combustion of ammonia in the presence of excess oxygen yields NO2 and H20:
4 NH3 (g) + 7 02 (g) → 4 NO2 (g)
+ 6 H2O (g)
The combustion of 174 g of ammonia consumes
g of oxygen.
Atomic weights: N=14.01, H=1.01, O=15.99. Input values only with 2 decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F017b98cd-369d-4c45-bb44-4703038e4600%2F8800ec54-8e3d-4fb0-b0ac-7e24ce80b0c0%2Fymopz8e_processed.png&w=3840&q=75)
Transcribed Image Text:The combustion of ammonia in the presence of excess oxygen yields NO2 and H20:
4 NH3 (g) + 7 02 (g) → 4 NO2 (g)
+ 6 H2O (g)
The combustion of 174 g of ammonia consumes
g of oxygen.
Atomic weights: N=14.01, H=1.01, O=15.99. Input values only with 2 decimal places.
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