The color distribution of plain M&Ms are claimed to be 18% green, 22% orange, 18% yellow, 22% blue, 10% red, and 10% brown. Test the claim at the 0.1 significance level. Complete the table. Round all answers to three decimal places. Category Observed Frequency Expected Frequency Residual green 26 orange 29 yellow 41 blue 23 red 22 brown 26 HoHo : pgreen = 0.18; porange = 0.22; pyellow = 0.18; pblue = 0.22; pred = 0.1; pbrown = 0.1 H1H1: at least one is different Original claim = Select an answer H₁ H₀ Enter the critical value, along with the significance level and degrees of freedom χ2χ2(αα,df) below the graph. (Graph is for illustration only. No need to shade.) X2Χ2(,) = (Round to three decimal places.) Test Statistic = (Round to three decimal places.) p-value= (Round to four decimal places.) Decision: Select an answer Reject the null hypothesis Fail to reject the null hypothesis Accept the alternative hypothesis Accept the null hypothesis Conclusion: Select an answer There is not sufficient evidence to warrant rejection of The sample data supports There is sufficient evidence to warrant rejection of There is not enough evidence to support the claim that the color distribution of plain M&Ms is 18% green, 22% orange, 18% yellow, 22% blue, 10% red, and 10% brown. Submit QuestionQuestion 6
The color distribution of plain M&Ms are claimed to be 18% green, 22% orange, 18% yellow, 22% blue, 10% red, and 10% brown. Test the claim at the 0.1 significance level. Complete the table. Round all answers to three decimal places.
| Category | Observed Frequency |
Expected Frequency |
Residual |
|---|---|---|---|
| green | 26 | ||
| orange | 29 | ||
| yellow | 41 | ||
| blue | 23 | ||
| red | 22 | ||
| brown | 26 |
HoHo : pgreen = 0.18; porange = 0.22; pyellow = 0.18; pblue = 0.22; pred = 0.1; pbrown = 0.1
H1H1: at least one is different
Enter the critical value, along with the significance level and degrees of freedom χ2χ2(αα,df) below the graph. (Graph is for illustration only. No need to shade.)
(Round to three decimal places.)
Test Statistic = (Round to three decimal places.)
p-value=
(Round to four decimal places.)
Decision: Select an answer Reject the null hypothesis Fail to reject the null hypothesis Accept the alternative hypothesis Accept the null hypothesis
Conclusion: Select an answer There is not sufficient evidence to warrant rejection of The sample data supports There is sufficient evidence to warrant rejection of There is not enough evidence to support the claim that the color distribution of plain M&Ms is 18% green, 22% orange, 18% yellow, 22% blue, 10% red, and 10% brown.
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