The color distribution of plain M&Ms are claimed to be 16% green, 20% orange, 14% yellow, 24% blue, 13% red, and 13% brown. Test the claim at the 0.01 significance level. Complete the table. Round all answers to three decimal places. Category Observed Frequency Expected Frequency Residual green 31 orange 47 yellow 34 blue 38 red 15 brown 29 HoHo : pgreen = 0.16; porange = 0.20; pyellow = 0.14; pblue = 0.24; pred = 0.13; pbrown = 0.13 H1H1: at least one is different Original claim = Select an answer H₁ H₀ Enter the critical value, along with the significance level and degrees of freedom χ2χ2(αα,df) below the graph. (Graph is for illustration only. No need to shade.) X2Χ2(,) = (Round to three decimal places.) Test Statistic = (Round to three decimal places.) p-value= (Round to four decimal places.) Decision: Select an answer Fail to reject the null hypothesis Accept the null hypothesis Reject the null hypothesis Accept the alternative hypothesis Conclusion: Select an answer The sample data supports There is sufficient evidence to warrant rejection of There is not enough evidence to support There is not sufficient evidence to warrant rejection of the claim that the color distribution of plain M&Ms is 16% green, 20% orange, 14% yellow, 24% blue, 13% red, and 13% brown.
The color distribution of plain M&Ms are claimed to be 16% green, 20% orange, 14% yellow, 24% blue, 13% red, and 13% brown. Test the claim at the 0.01 significance level. Complete the table. Round all answers to three decimal places.
| Category | Observed Frequency |
Expected Frequency |
Residual |
|---|---|---|---|
| green | 31 | ||
| orange | 47 | ||
| yellow | 34 | ||
| blue | 38 | ||
| red | 15 | ||
| brown | 29 |
HoHo : pgreen = 0.16; porange = 0.20; pyellow = 0.14; pblue = 0.24; pred = 0.13; pbrown = 0.13
H1H1: at least one is different
Enter the critical value, along with the significance level and degrees of freedom χ2χ2(αα,df) below the graph. (Graph is for illustration only. No need to shade.)
(Round to three decimal places.)
Test Statistic = (Round to three decimal places.)
p-value=
(Round to four decimal places.)
Decision: Select an answer Fail to reject the null hypothesis Accept the null hypothesis Reject the null hypothesis Accept the alternative hypothesis
Conclusion: Select an answer The sample data supports There is sufficient evidence to warrant rejection of There is not enough evidence to support There is not sufficient evidence to warrant rejection of the claim that the color distribution of plain M&Ms is 16% green, 20% orange, 14% yellow, 24% blue, 13% red, and 13% brown.
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