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The clock reaction reaction: H2O2 + 3I- + 2H+ → I3- + 2H2O occurs through the following mechanism.                                                                                H2O2 + H+ ↔ H3O2+ (fast equilibrium K1 ) H3O2+ + I- → H2O + HOI  (slow k2 )  HOI + I- → OH- + I2           (fast k3) OH- + H+ → H2O (fast  k4) I2 + I- → I3- (fast k5) What is the rate law for this reaction?

The clock reaction reaction: H2O2 + 3I- + 2H+ → I3- + 2H2O occurs through the following mechanism.                                                                                H2O2 + H+ ↔ H3O2+ (fast equilibrium K1 ) H3O2+ + I- → H2O + HOI  (slow k2 )  HOI + I- → OH- + I2           (fast k3) OH- + H+ → H2O (fast  k4) I2 + I- → I3- (fast k5) What is the rate law for this reaction?

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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The clock reaction reaction: H2O2 + 3I- + 2H+ → I3- + 2H2O occurs through the following mechanism.                                                                               

  1. H2O2 + H+ ↔ H3O2+ (fast equilibrium K1 )
  2. H3O2+ + I- → H2O + HOI  (slow k2 )
  3.  HOI + I- → OH- + I2           (fast k3)
  4. OH- + H+ → H2O (fast  k4)
  5. I2 + I- → I3- (fast k5)

What is the rate law for this reaction?

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