The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm. Use inear approximation to estimate the maximum error in the calculated surface area. Round to two decimal places. Estimate the relative error in the calculated surface area. Enter a percent rounded to 2 decimal places. %

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter0: Preparing For Algebra
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The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm. Use
linear approximation to estimate the maximum error in the calculated surface area. Round to two
decimal places.
Estimate the relative error in the calculated surface area. Enter a percent rounded to 2 decimal
places.
%
Transcribed Image Text:The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm. Use linear approximation to estimate the maximum error in the calculated surface area. Round to two decimal places. Estimate the relative error in the calculated surface area. Enter a percent rounded to 2 decimal places. %
sin(12a)
Use l'Hopital's Rule to evaluate lim
. Then determine the limit using limit laws and
commonly known limits.
Use l'Hopital's rule to rewrite the given limit so that it is not an indeterminate form.
sin(12a)
lim
lim
12
Choose the limit equivalent to the given limit that can be evaluated using limit laws and commonly
known limits.
sin(12a)
O lim
12 cos(12r)
lim
12x
sin(12a)
lim
lim (12 cos a)
sin(12a)
lim
sin 12
= lim
12
sin(12a)
O lim
12 sin(12a)
lim
12z
sin(12z)
The limit found by using either method is lim
12
%3D
Transcribed Image Text:sin(12a) Use l'Hopital's Rule to evaluate lim . Then determine the limit using limit laws and commonly known limits. Use l'Hopital's rule to rewrite the given limit so that it is not an indeterminate form. sin(12a) lim lim 12 Choose the limit equivalent to the given limit that can be evaluated using limit laws and commonly known limits. sin(12a) O lim 12 cos(12r) lim 12x sin(12a) lim lim (12 cos a) sin(12a) lim sin 12 = lim 12 sin(12a) O lim 12 sin(12a) lim 12z sin(12z) The limit found by using either method is lim 12 %3D
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