.1//7 7 arccos x x² dx V1- x 1 –

Q: 1.

A: ∫-11∫-1-x20x2+y2dydxConvert to polar coordinates:=∫π2π∫01r2rdrdθ=∫π2π13dθ=π3

Q: .3 1 J2 dx=? x² – 4x+5

A:

Q: 1 (2x-3)4 4. S dx

A: Follow the procedure given below.

Q: -9 dx (3x + 1)² 1

A: Solution: ∫1∞-9(3x+1)2dxTake the constant out=-9×∫1∞1(3x+1)2dx

Q: (3-5x) 2. (3- 1y(r – 1) d (3х - 1) (х —1)2

A:

Q: 1 dx х x³Vx²

A: We have to integrate  ∫22 1x3x2-1 dx.

Q: 1/x dx 3?

A:

Q: 8. Find for y=√√4x (arcsin(x²+2x)) dx

A:

Q: 5. Change of variable 2 x dx 3x+1 a.

A: Given function, ∫12x3x+1dx

Q: Se-¹x² dx. е

A: Given query is to find the integral.

Q: (2x³-9x²+2) dx from x = 6 to x = 11

A: Given: ∫2x3-9x2+2dx   from x=6 to x=11

Q: 1 7. 2x (x2 – 1) dx -1

A: Distribute 2x

Q: If y = 9csc²-x 3 O -18 csc2> 3 -6 csc²}x• 3

A: Given: y=9csc213x

Q: 1. Find dx if it exists.

A:

Q: X = Ys e %3D (ras.t) %3D (2.1,0)

A: Here we have given u in terms of x,y,z and x,y,z in terms of r,s,t , We use above given relations to…

Q: 2. x x+4 dx

A:

Q: Compute the following.   d/dx(3x+5)2 x=1

A:

Q: x² + da

A: Evaluate ∫x-1x2x2+255dx=?

Q: 1- S dx -4 4

A:

Q: dx Evaluate • (1–2x)² 0 1 1 2 O-1 o 1 2

A: We have ∫-∞0dx(1-2x)2

Q: 3 S Inx dx 1

A:

Q: 1/2 4 dx VI - x

A:

Q: 1. [²+3x - 4)dx

A:

Q: 2 1n x. 9. dx

A: Derivative: The chain rule states  ddxfgx=f'(gx)·g'(x) The derivative formulas are ddx(ex)=exddx(ln…

Q: f. (5 x 5)+5'D 1- g. (3 32) 31 =

A: In these questions we have to find the values of the given statement by solving brackets and then by…

Q: b. sin? () = 2 over [0, 2n) %3D

A: EXPLANATION

Q: 3r -

A: ∫12dx3x-2Find the Integral value.

Q: .5 Find dx 15 .5 X' dx 15

A: According to the rules of differentiation the result to be used here is as. Here 'c' is a constant.

Q: . If x = 3t² - 2t, find the value of dx/dy when t = 5

A: The given function is x=3t2-2t.