The circular disk of 145-mm radius has a mass of 38 kg with centroidal radius of gyration k bar = 25 mm and has a concentric circular groove of 55-mm radius cut into it. A steady force Tis applied at an angle theta to a cord wrapped around the groove as shown. If T = 40 N, theta = 0, mu_s = 0.11, and mu_k = 0.09, determine the angular acceleration a of the
The circular disk of 145-mm radius has a mass of 38 kg with centroidal radius of gyration k bar = 25 mm and has a concentric circular groove of 55-mm radius cut into it. A steady force Tis applied at an angle theta to a cord wrapped around the groove as shown. If T = 40 N, theta = 0, mu_s = 0.11, and mu_k = 0.09, determine the angular acceleration a of the
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter10: Virtual Work And Potential Energy
Section: Chapter Questions
Problem 10.20P: Locate the instant center of rotation of bar AB for each case shown.
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The circular disk of 145-mm radius has a mass of 38 kg with centroidal radius of gyration k bar = 25 mm and has a concentric circular groove of 55-mm radius cut into it. A steady force Tis applied at an angle theta to a cord wrapped around the groove as shown. If T = 40 N, theta = 0, mu_s = 0.11, and mu_k = 0.09, determine the angular acceleration a of the

Transcribed Image Text:The circular disk of 145-mm radius has a mass of 38 kg with centroidal radius of gyration k = 125 mm and has a
concentric circular groove of 55-mm radius cut into it. Ā steady force T is applied at an angle 0 to a cord wrapped around
the groove as shown. If T = 40 N, 0 = 0, µs = 0.11, and Hk = 0.09, determine the angular acceleration a of the disk, the
acceleration a of its mass center G, and the friction force F which the surface exerts on the disk. The angular acceleration
a is positive if counterclockwise, negative if clockwise; the acceleration a is positive if to the right, negative if to the left;
and the friction force F is positive if to the right, negative if to the left.
m = 38 kg
E = 125 mm
145 mm
T
55
mm
G
lg = 0.11)
Uk = 0.09
Answers:
a =T2.25296
Drad/s2
a =
-0.32667
Um/s²
F =
-27.5862
UN
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