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The circuit shown has reached steady state before the switch is closed at time t = 0. Determine the inductor current, i(t), for time t > 0. Answer: i(t) = 20-10e-10t (sin(20t) + 2 cos(20t)) mA t=0 w 4000 10V 1000 250μF 10H i(t)

The circuit shown has reached steady state before the switch is closed at time t = 0. Determine the inductor current, i(t), for time t > 0. Answer: i(t) = 20-10e-10t (sin(20t) + 2 cos(20t)) mA t=0 w 4000 10V 1000 250μF 10H i(t)

Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter24: Resistive-inductive-capacitive Parallel Circuits
Section: Chapter Questions
Problem 1RQ: An AC circuit contains a 24 resistor, a 15.9-mH inductor, and a 13.3F capacitor connected in...
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Can you show why the answer is that for this question using second order differential equations, instead of laplace transforms

The circuit shown has reached steady state before the switch is closed at time t = 0. Determine the inductor current, i(t), for time t > 0. Answer: i(t) = 20-10e-10t (sin(20t) + 2 cos(20t)) mA t=0 w 4000 10V 1000 250μF 10H i(t)
Transcribed Image Text:The circuit shown has reached steady state before the switch is closed at time t = 0. Determine the inductor current, i(t), for time t > 0. Answer: i(t) = 20-10e-10t (sin(20t) + 2 cos(20t)) mA t=0 w 4000 10V 1000 250μF 10H i(t)
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