The circuit in (Figure 1) is scaled so that the 4 k resistor is replaced by a 20 k resistor and the 5 nF capacitor is replaced by a 100 pF capacitor. Part A What is the scaled value of inductor? Figure 300u(t) V 1 of 1 ☐ ΜΑ Units L= Value Submit Request Answer Part B ? Choose the correct expression for v, in the scaled circuit? Vo= (256e-400000t vo (256e 400000 = Vo= (4e +4e-100000+)u(t) V -4e-100000+)u(t) V -400000t 256e-100000+)u(t) V Vo= (4e 400000+ +256e-100000+)u(t) V 4 ΚΩ 21 ΚΩ www + Submit Request Answer + Vo80 mH 5 nF i. Provide Feedback
The circuit in (Figure 1) is scaled so that the 4 k resistor is replaced by a 20 k resistor and the 5 nF capacitor is replaced by a 100 pF capacitor. Part A What is the scaled value of inductor? Figure 300u(t) V 1 of 1 ☐ ΜΑ Units L= Value Submit Request Answer Part B ? Choose the correct expression for v, in the scaled circuit? Vo= (256e-400000t vo (256e 400000 = Vo= (4e +4e-100000+)u(t) V -4e-100000+)u(t) V -400000t 256e-100000+)u(t) V Vo= (4e 400000+ +256e-100000+)u(t) V 4 ΚΩ 21 ΚΩ www + Submit Request Answer + Vo80 mH 5 nF i. Provide Feedback
Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter8: Basic Electric Motors
Section: Chapter Questions
Problem 25RQ: List the five capacitor replacement rules.
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Please answer in typing format
![The circuit in (Figure 1) is scaled so that the 4 k resistor is replaced by a 20 k resistor
and the 5 nF capacitor is replaced by a 100 pF capacitor.
Part A
What is the scaled value of inductor?
Figure
300u(t) V
1 of 1
☐
ΜΑ
Units
L= Value
Submit
Request Answer
Part B
?
Choose the correct expression for v, in the scaled circuit?
Vo=
(256e-400000t
vo (256e 400000
=
Vo= (4e
+4e-100000+)u(t) V
-4e-100000+)u(t) V
-400000t
256e-100000+)u(t) V
Vo= (4e 400000+ +256e-100000+)u(t) V
4 ΚΩ
21 ΚΩ
www
+
Submit
Request Answer
+
Vo80 mH
5 nF
i.
Provide Feedback](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5d6d0075-824a-4854-8779-38d5f2450d09%2F078a0d2d-b064-4a24-ac56-e6497dbb91c6%2Fxbj392c_processed.png&w=3840&q=75)
Transcribed Image Text:The circuit in (Figure 1) is scaled so that the 4 k resistor is replaced by a 20 k resistor
and the 5 nF capacitor is replaced by a 100 pF capacitor.
Part A
What is the scaled value of inductor?
Figure
300u(t) V
1 of 1
☐
ΜΑ
Units
L= Value
Submit
Request Answer
Part B
?
Choose the correct expression for v, in the scaled circuit?
Vo=
(256e-400000t
vo (256e 400000
=
Vo= (4e
+4e-100000+)u(t) V
-4e-100000+)u(t) V
-400000t
256e-100000+)u(t) V
Vo= (4e 400000+ +256e-100000+)u(t) V
4 ΚΩ
21 ΚΩ
www
+
Submit
Request Answer
+
Vo80 mH
5 nF
i.
Provide Feedback
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