The circuit designer wants to change the values of R and R2 so that the design output voltage v, = 5 V is achieved when the load resistance is R, = 200 kN rather than at no-load. The actual output voltage must not drop below 4.5 V when RL, = 100 kn. What is the smallest resistor value that can be used for R,? Express your answer in kl to three significant figures.

Introductory Circuit Analysis (13th Edition)
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he design output
Learning Goal:
To understand the effect of the load resistance on the output voltage for a voltage divider.
The circuit shown below can be viewed as a voltage divider. This circuit can be used to generate a new lower voltage v, from an input DC voltage v,
R
R
R,
When there is no load attached, the output voltage is vo =
ReaRe Ug. The load is attached in parallel with R2. The equivalent resistance of the load and R2 in parallel will always be smaller than the resistance of R2
Ra
R, (1+Ra/R2)+R,
alone, so the output voltage must decrease. For a given load resistance RL, the output voltage is v, =
The circuit designer wants to change the values of R and R, so that the design output voltage v, = 5 V is achieved when the load resistance is RI, = 200 k rather than at no-load. The actual output voltage must
not drop below 4.5 V when RI, = 100 kN. What is the smallest resistor value that can be used for R, ?
Express your answer in kN to three significant figures.
> View Available Hint(s)
VO AEO If vec
?
R = 6.67
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 4 attempts remaining
Transcribed Image Text:he design output Learning Goal: To understand the effect of the load resistance on the output voltage for a voltage divider. The circuit shown below can be viewed as a voltage divider. This circuit can be used to generate a new lower voltage v, from an input DC voltage v, R R R, When there is no load attached, the output voltage is vo = ReaRe Ug. The load is attached in parallel with R2. The equivalent resistance of the load and R2 in parallel will always be smaller than the resistance of R2 Ra R, (1+Ra/R2)+R, alone, so the output voltage must decrease. For a given load resistance RL, the output voltage is v, = The circuit designer wants to change the values of R and R, so that the design output voltage v, = 5 V is achieved when the load resistance is RI, = 200 k rather than at no-load. The actual output voltage must not drop below 4.5 V when RI, = 100 kN. What is the smallest resistor value that can be used for R, ? Express your answer in kN to three significant figures. > View Available Hint(s) VO AEO If vec ? R = 6.67 Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
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