The chart below shows the first five successive ionizations of element M. What is the formula of the ionic compound formed when element Mcombines with the carbonate anion.enthalpy (kl/mol)160001400012000100008000600040002000012345Successive ionization energiesClick here if the image doesn't load. BO M₂(COsh○ MCO○ M₂COO MICO₂h

The energy required to remove a valence electron from a gaseous atom or ion is called ionization…

Answered: The chart below shows the first five…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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f21 > Macmillan Learning Consider an ionic compound, MX3, composed of generic metal M and generic gaseous halogen X. • The enthalpy of formation of MX3 is AH = -889 kJ/mol. ⚫ The enthalpy of sublimation of M is AH sub 127 kJ/mol. • The first, second, and third ionization energies of M are IE₁ = 569 kJ/mol, IE2 1735 kJ/mol, and IE3 2683 kJ/mol. • The electron affinity of X is AHEA = -357 kJ/mol. (Refer to the hint). ⚫ The bond energy of X2 is BE = 241 kJ/mol. Determine the lattice energy of MX3. AH lattice= kJ/mol
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Can someone please fill this out for N2-? In my mind ther are 11 electrons. Nitrogen has 5 valence electrons, so 5*2+1=11, but I keep asking about this and people are telling me that there are 15 electrons. Where is the 7*2+1=15 coming from? And this is the picture I have to use for this quetion. Everyone keeps drawing a different diagram to fit in the 15 electrons. I'm so confused about this. I believe the molecular electron configuration is: (σ2s)2(σ*2s)2(π2p)2(π2p)2(σ2p)2(π*2p)1 Correct? That is 11, so I'm not sure why I keep getting different answers about this. Can you please help? Thanks
Estimate the charge of each oxygen and nitrogen atom respectively for the organic molecule shown below: H :02 O O (1) = о 0 (2) о 0 (3) O N (1) = O N (1) =

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