The cell membrane in a nerve cell has a thickness of 0.135 LT, Approximating the cell membrane as a parallel-plate capacitor with a surface charge density of 6.05E-6 C/m², calculate the electric field within the membrane. Submit Answer Tries 0/32 Calculate the electric field within the membrane, if the thickness of the membrane were quadrupled.
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- A parrallel plate capacitor has circular cross-section with a radius R and has a charge that varias Q(t). Take the spacing between the plates to be small so that you can assume the electric field is uniform for r < R and vanishes for r>R. Answer in terms of Q(t) and its derivatives.(a) What is the magnitude of the electric field inside the capacitor as a function of time? (E(t), find the surface charge density to find the electric field) (b) Inside the capacitor (for r<R), what is the magnetic field as a fucntion of time at a distance r from the center? Use Ampere-Maxwel law with displacement current. E(t) is uniform inside and zero outside.Find the electric field at P in the figure shown below. (Take r = 1.4 m and 0 = 41°. Measure the angle counterclockwise from the positive x-axis.) magnitude direction 9 9 O "' " Ꮎ = 10×10-⁹C 9.0 PAn air-filled parallel-plate capacitor has plates of area 2.60 cm2 separated by 1.80 mm. The capacitor is connected to a(n) 17.0 V battery. (a) Find the value of its capacitance. 1.27 pF (b) What is the charge on the capacitor? 21.7 pC .(c)..What.is.the.magnitude of the uniform electric field between the plates? Enter a number. differs from the correct answer by more than 10%. Double check your calculations. N/C Need Help? Read It
- The cell membrane in a nerve cell has a thickness of 0.12 µm. Approximating the cell membrane as a parallel-plate capacitor with a surface charge density of 5.9 x 10-6C/m², find the electric field within the membrane.A large hollow sphere is composed of a uniformaly positive charge gel. The hollow cavity has a radius of R and the outer radius of the sphere has radius 4R. What is the total electric field energy within the entire sphere computed by using electric fields?Assume that a negative charge is placed on the top plate of a capacitor. A positive charge is placed on the bottom plate. What is the magnitude of the electric field E between the plates?
- The electric flux density of a charge distribution with spherical symmetry is given by (a³po -âr, r2 a 3r2 rpo D = r a C-Levitation: The largest electric field strength you can create in air before dielectric breakdown (a spark) occurs is about 3.0 x 10°V/m. Suppose you created an electric field with this strength – pointing directly upward – between a set of parallel plates that are 9.9cm apart. You want to use this system to levitate water droplets with a mass of 1.8g. (a) How much charge would you have to put on a droplet to make it levitate? (b) Suppose that 43 charged droplets are levitating and the field strength suddenly drops by 24 percent, to about 2.3 x 106 V/m, how quickly would the droplets accelerate? Eparallel-plate capacitors are widely used in electronics such as preventing direct current leakage. An electric field is generated between a pair of plates that has a surface charge density of 7.70 x 10^-6 C/m^2 The plates are seperated by 0.49 um. a) what is the magnitude of the electric field between the plates ? b) suppose the thickness of the plates doubled, would my answer increase, decrease, or remain the same?