The electric flux density of a charge distribution with spherical symmetry is given by(a³po-âr,r2 a3r2rpoD =r< a3Finda- The potential for r 2 ab- The energy stored in the region r < aDetermine the volume charge density for the region r > aC-

Given data, Distribution of electric field is given by as following :-

The electric flux density of a charge distribution with spherical symmetry is given by °d. D = 3r2 τρο (a³ - âr, r 2 a r< a 3 Find a- The potential for r 2 a b- The energy stored in the region r < a c- Determine the volume charge density for the regionr z a

The electric flux density of a charge distribution with spherical symmetry is given by °d. D = 3r2 τρο (a³ - âr, r 2 a r< a 3 Find a- The potential for r 2 a b- The energy stored in the region r < a c- Determine the volume charge density for the regionr z a

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Question

The electric flux density of a charge distribution with spherical symmetry is given by
(a³po
-âr,
r2 a
3r2
rpo
D =
r< a
3
Find
a- The potential for r 2 a
b- The energy stored in the region r < a
Determine the volume charge density for the region r > a
C-

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Ra1 +9 -9 Rea Consider two concentric spherical conductors, separated by an isolating material with (absolute) permittivity e. The two conductors have radius R1 and R2, they are put on a potential V and V2, which leads to a charge +q and –q sitting on them, respectively. By the problem's spherical symmetry, we see that the charge on each conductor is distributed uniformly, and that, in spherical coordinates, the electric field between the two conductors is of the form E(r) = -E(r) er. Determine the capacity C using the following steps: 1. Use Gauss's Law in integral form, with N a ball of radius r (R2 < r < R1), to find an expression for E(r) in terms of q. 2. Calculate AV = Vị – V2 using the formula - E•dr Δν and with C the black line segment indicated on the drawing (parallel with e,). 3. The capacity now follows from C = q/AV.