The cart and its contents have a total mass of 4500 kg and a center of gravity at G as shown in Figure Q4. The coefficient of static friction between the wheels and the tracks is 4 = 0.4 when the wheels are locked. The normal forces acting on the wheels at (A and B) are independent as to whether the wheels are locked or not. Therefore, 10kN 0.9 m 0.15 m 0.6 m 1.5 m

International Edition---engineering Mechanics: Statics, 4th Edition
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ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
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Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.35P: The weight of the cylindrical tank is negligible in comparison to the weight of water it contains...
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The cart and its contents have a total mass of 4500 kg and a center of gravity at G as shown in
Figure Q4. The coefficient of static friction between the wheels and the tracks is l = 0.4 when
the wheels are locked. The normal forces acting on the wheels at (A and B) are independent as
to whether the wheels are locked or not. Therefore,
10kN
0.9 m
0.15 m
: 0.6 m
土
1.5 m
Figure Q4: The cart.
Transcribed Image Text:The cart and its contents have a total mass of 4500 kg and a center of gravity at G as shown in Figure Q4. The coefficient of static friction between the wheels and the tracks is l = 0.4 when the wheels are locked. The normal forces acting on the wheels at (A and B) are independent as to whether the wheels are locked or not. Therefore, 10kN 0.9 m 0.15 m : 0.6 m 土 1.5 m Figure Q4: The cart.
(c)
Calculate the normal force acting on the rear wheels at A when the brakes at both A and
B are locked.
(d)
Analyze either the crate moved or not due to the 10 kN applied load.
Transcribed Image Text:(c) Calculate the normal force acting on the rear wheels at A when the brakes at both A and B are locked. (d) Analyze either the crate moved or not due to the 10 kN applied load.
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