The car on the left in the photo and in Fig 12-2 moves in a straight line such that for a short time its velocity is defined by ( + 2) n/s, where ris in seconds. Determine its position and acceleration when t=3 When t0-0 SOLUTION Coordinate System. The position coordinate extends from the fixed origin O to the car, positive to the right. Position. Since f(). the car's position can be determined from ds/di, since this equation relates , , and t. Noting that 0 when t=0 we have - + 2) (4) 2nd When -3 -o+ o - n Acceleration. Since f(), the acceleration is determined from de/di, since this equation relates a, , and. An o + 20 (4) When t 3 -0) +2- 20/- NOTE: The formulas for constant acceleration cannot be used to solve this problem, because the acceleration is a function of time. Engineering Machanics / Dynamics First Level/2nd / 2019/2020
The car on the left in the photo and in Fig 12-2 moves in a straight line such that for a short time its velocity is defined by ( + 2) n/s, where ris in seconds. Determine its position and acceleration when t=3 When t0-0 SOLUTION Coordinate System. The position coordinate extends from the fixed origin O to the car, positive to the right. Position. Since f(). the car's position can be determined from ds/di, since this equation relates , , and t. Noting that 0 when t=0 we have - + 2) (4) 2nd When -3 -o+ o - n Acceleration. Since f(), the acceleration is determined from de/di, since this equation relates a, , and. An o + 20 (4) When t 3 -0) +2- 20/- NOTE: The formulas for constant acceleration cannot be used to solve this problem, because the acceleration is a function of time. Engineering Machanics / Dynamics First Level/2nd / 2019/2020
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Transcribed Image Text:Engineering Mechanics / Dynamics
Civil Engineering Department
First Level/2nd /2019/2020
Dr.Majid Mohammed Kharnoob
The car on the left in the photo and in Fig. 12-2 moves in a straight
line such that for a short time its velocity is defined by
= (3 + 21) f/s, where t is in seconds. Determine its position and
acceleration when 3s. When 0, 0.
Fig 12-2
SOLUTION
Coordinate System. The position coordinate extends from the fixed
origin O to the car, positive to the right.
Position. Since e = /(1). the car's position can be determined from
ds/dt, since this equation relates e, s, and t. Noting that s0
when t=0, we have
(4)
= (3 + 2)
+ 2ndt
When I3s,
3= (3 + o = 36n
Ans
Acceleration. Since e = f(0), the acceleration is determined from
a- de/dt, since this equation relates a, e, and t.
de
( + 20
dt dt
(4)
-6 + 2
Whent3s.
a= 63) +2- 20 ft/s
Ans
NOTE: The formulas for constant acceleration cannot be used to solve
this problem, because the acceleration is a function of time.
29
Engineering Mechanics / Dynamics
Civil Engineering Department
First Level/2nd / 2019/2020
Dr.Majid Mohammed Kharnoob
Question: - A motorcyclist travels along a straight road
at a speed of (27 m/s). When the brakes are applied, the
motorcycle decelerates at a rate of (-61 m/s). Find the
distance the motorcycle travels before it stops?
rr/YA
30
Engineering Mechanics / Dynamics
Civil Engineering Department
First Level/2nd / 2019/2020
Dr.Majid Mohammed Kharnoob
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