Engineering Mechanics / DynamicsCivil Engineering DepartmentFirst Level/2nd /2019/2020Dr.Majid Mohammed KharnoobThe car on the left in the photo and in Fig. 12-2 moves in a straightline such that for a short time its velocity is defined by= (3 + 21) f/s, where t is in seconds. Determine its position andacceleration when 3s. When 0, 0.Fig 12-2SOLUTIONCoordinate System. The position coordinate extends from the fixedorigin O to the car, positive to the right.Position. Since e = /(1). the car's position can be determined fromds/dt, since this equation relates e, s, and t. Noting that s0when t=0, we have(4)= (3 + 2)+ 2ndtWhen I3s,3= (3 + o = 36nAnsAcceleration. Since e = f(0), the acceleration is determined froma- de/dt, since this equation relates a, e, and t.de( + 20dt dt(4)-6 + 2Whent3s.a= 63) +2- 20 ft/sAnsNOTE: The formulas for constant acceleration cannot be used to solvethis problem, because the acceleration is a function of time.29Engineering Mechanics / DynamicsCivil Engineering DepartmentFirst Level/2nd / 2019/2020Dr.Majid Mohammed KharnoobQuestion: - A motorcyclist travels along a straight roadat a speed of (27 m/s). When the brakes are applied, themotorcycle decelerates at a rate of (-61 m/s). Find thedistance the motorcycle travels before it stops?rr/YA30Engineering Mechanics / DynamicsCivil Engineering DepartmentFirst Level/2nd / 2019/2020Dr.Majid Mohammed Kharnoob

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The car on the left in the photo and in Fig 12-2 moves in a straight line such that for a short time its velocity is defined by ( + 2) n/s, where ris in seconds. Determine its position and acceleration when t=3 When t0-0 SOLUTION Coordinate System. The position coordinate extends from the fixed origin O to the car, positive to the right. Position. Since f(). the car's position can be determined from ds/di, since this equation relates , , and t. Noting that 0 when t=0 we have - + 2) (4) 2nd When -3 -o+ o - n Acceleration. Since f(), the acceleration is determined from de/di, since this equation relates a, , and. An o + 20 (4) When t 3 -0) +2- 20/- NOTE: The formulas for constant acceleration cannot be used to solve this problem, because the acceleration is a function of time. Engineering Machanics / Dynamics First Level/2nd / 2019/2020

The car on the left in the photo and in Fig 12-2 moves in a straight line such that for a short time its velocity is defined by ( + 2) n/s, where ris in seconds. Determine its position and acceleration when t=3 When t0-0 SOLUTION Coordinate System. The position coordinate extends from the fixed origin O to the car, positive to the right. Position. Since f(). the car's position can be determined from ds/di, since this equation relates , , and t. Noting that 0 when t=0 we have - + 2) (4) 2nd When -3 -o+ o - n Acceleration. Since f(), the acceleration is determined from de/di, since this equation relates a, , and. An o + 20 (4) When t 3 -0) +2- 20/- NOTE: The formulas for constant acceleration cannot be used to solve this problem, because the acceleration is a function of time. Engineering Machanics / Dynamics First Level/2nd / 2019/2020

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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