Find VA/B and VA/B-200 my-- xBAnswers:VA/B = ( ii+ ij) m/sim/sVA/B = Car A is traveling at the constant speed of 50 km/h as it rounds the circular curve of 200-m radius and at the instant represented is atthe position e = 43°. Car B is traveling at the constant speed of 60 km/h and passes the center of the circle at this same instant. Car A islocated with respect to car B by polar coordinates r and O with the pole moving with B. For this instant determine va/R and the values ofi and O as measured by an observer in car B.200 m

Given data, Velocity of car A = 50 kmph = 13.89 m/s Velocity of car B = 60 kmph = 16.67 m/s Angle…

Answered: Car A is traveling at the constant…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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2/108 The figure shows two possible paths for negotiating an unbanked turn on a horizontal portion of a race course. Path A-A follows the centerline of the road and has a radius of curvature PA = 85 m, while path B-B uses the width of the road to good advan- tage in increasing the radius of curvature to PB = 200 m. If the drivers limit their speeds in their curves so that the lateral acceleration does not exceed 0.8g, determine the maximum speed for each path. A B PB = 200 m PA = 85 m 4 B 2/109 From an = ²₁ U=√an = √0.8g 12 A√0.89 PA=0.8 (1.81(85) = 25.8 m/s Ug = √0.8918 = √0.8 (1.81)(200) = 39.6 m/s Path BB offers a considerable advantage.
The concept of variable banking for racetrack turns is shown in the figure. If the two radii of curvature are PA = 291 ft and PB = 312 ft for cars A and B, respectively, determine the maximum speed for each car. The coefficient of static friction is us = 0.83 for both cars. Answers: VA = VB= i i 15° B 22° ft/sec ft/sec
SITUATION. The a-t curve for a particle having a rectilinear motion is shown in the figure. At t=0, the velocity is 30 ft/s and the particle is at the origin. a (ft/s²) 0 +10 -10 Determine the maximum velocity in ft/sec. 7 t (sec) 13 -3
1. The right side of a truck has a constant speed of 6 m/s as it turns to the left on a path with of curvature of 16m. The direction of the angular velocity vector of the rear right wheel is changing as the truck turns. What is the magnitude and direction (relative to the truck) of the angular acceleration vector, &, of the rear right wheel? SIDE VIEW REAR R = 0.3m p = 16 m TOP VIEW VT = 6 m/s FRONT VT = 6 m/s
The radius of a highway curve is 120 m, and has an angle of 9.31° from the horizontal. The center of gravity of the car is located 0.80 m above the roadway and the distance between the two front wheels is 1.2 m. If the car has a total weight of 15 KN. a. Determine the normal acceleration and the velocity (in kph) of the car before overturning. b. Find the maximum velocity of the car could move along the curve so that there will be no outstanding pressure between the tires and the roadway. c. If the coefficient of kinetic friction is 0.60, what is the maximum velocity (in kph) of the car without sliding.
Determine the angular velocity 0 in rad/s of the radial line OA at this instant if the truck has a speed of 40.9 ft/s. r = 364 ft
A vehicle moves in a straight line such that for a short time its velocity v = (0.4t + 0.6vt) m/s where t is in second (ift3D0, s=0).Determine it position(s) when t-4sec? **
To anticipate the dip and the hump in the road, the driver of a car applies his brakes to produce a uniform deceleration. His speed is 100kph at the bottom A of the dip and 50 kph at the top C of the hump. The length of the road from A to C is 120m. The radius of curvature of the hump at C is 150m. The total acceleration at A is 3 m/s^2. Compute the radius of curvature at A.

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