2/108 The figure shows two possible paths for negotiatingan unbanked turn on a horizontal portion of a racecourse. Path A-A follows the centerline of the roadand has a radius of curvature PA = 85 m, whilepath B-B uses the width of the road to good advan-tage in increasing the radius of curvature toPB = 200 m. If the drivers limit their speeds intheir curves so that the lateral acceleration doesnot exceed 0.8g, determine the maximum speed foreach path.A BPB = 200 mPA = 85 m4B2/109 From an = ²₁ U=√an = √0.8g12A√0.89 PA=0.8 (1.81(85) = 25.8 m/sUg = √0.8918 = √0.8 (1.81)(200) = 39.6 m/sPath BB offers a considerable advantage.

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Engineering

Civil Engineering

e radius of cu wers limit their e lateral accele

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Unit Conversion

Standard units are also called SI units. SI units are used for measuring a physical quantity satisfying certain conditions. There are two types of units: fundamental units and derived units. Fundamental units are physical quantities that are independent, that is, they do not depend on other quantities like mass, length, or time. There are plenty of quantities in our lives which need to be measured and compared. Measuring is the comparison of a particular physical quantity with its reference value. A unit is a measure of a fixed physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with.

Question

2/108 The figure shows two possible paths for negotiating
an unbanked turn on a horizontal portion of a race
course. Path A-A follows the centerline of the road
and has a radius of curvature PA = 85 m, while
path B-B uses the width of the road to good advan-
tage in increasing the radius of curvature to
PB = 200 m. If the drivers limit their speeds in
their curves so that the lateral acceleration does
not exceed 0.8g, determine the maximum speed for
each path.
A B
PB = 200 m
PA = 85 m
4
B
2/109 From an = ²₁ U=√an = √0.8g
12
A√0.89 PA=0.8 (1.81(85) = 25.8 m/s
Ug = √0.8918 = √0.8 (1.81)(200) = 39.6 m/s
Path BB offers a considerable advantage.

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