For the simple truss shown in the picture the students are required to determine a combination of values for the cross-sectional area of the truss members and the angle 0 that will allow the structure to be both safe for example, the axial stresses developing within the truss elements are less than the yield stress fy = 500MPA and cheep, provide that the cost of the material is cost = 1.1£/kgr. Assume that the density of the material is 8100 kgr/m3. It is noted that the structural analysis has been already carried out for and the analytical relations expressing the internal forces have been provided in the picture.

For the simple truss shown in the picture the students are required to determine a combination of values for the cross-sectional area of the truss members and the angle 0 that will allow the structure to be both safe for example, the axial stresses developing within the truss elements are less than the yield stress fy = 500MPA and cheep, provide that the cost of the material is cost = 1.1£/kgr. Assume that the density of the material is 8100 kgr/m3. It is noted that the structural analysis has been already carried out for and the analytical relations expressing the internal forces have been provided in the picture.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

For the simple truss shown in the picture the students are required to
determine a combination of values for the cross-sectional area of the
truss members and the angle 0 that will allow the structure to be both
safe for example, the axial stresses developing within the truss elements
are less than the yield stress fy = 500MPA and cheep, provide that the
cost of the material is cost = 1.1£/kgr. Assume that the density of the
material is 8100 kgr/m³. It is noted that the structural analysis has been
already carried out for and the analytical relations expressing the internal
forces have been provided in the picture.
P=2000 KN
cost
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PEA
Tel
PAB
EA
Ray
E,A
lon
Pazo Ray/
Ray
Sime
Pascose + Pac ->
Parea -Pao coso Paca Ray coe
Ray cose
Sino

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determining total load of structure

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determination of member area & angle

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