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The Capacitor connected across the terminals of a black box has an initial voltage V(0) = -20V. The resulting current for t> 0 is: i(t) = 800e-25 μA Find: vo(t)t 20 -25t 800e μA :1.6με O a. Vo(t) = +20 e 25t -40V o Vo(t) = -20 e 25t v Oc Vo(t) = +20 e-25t v O d. Vo(t) = -20 e 25t + 40 V O No 11 - Vo + Black BOX

The Capacitor connected across the terminals of a black box has an initial voltage V(0) = -20V. The resulting current for t> 0 is: i(t) = 800e-25 μA Find: vo(t)t 20 -25t 800e μA :1.6με O a. Vo(t) = +20 e 25t -40V o Vo(t) = -20 e 25t v Oc Vo(t) = +20 e-25t v O d. Vo(t) = -20 e 25t + 40 V O No 11 - Vo + Black BOX

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The Capacitor connected across the terminals of a black box has an initial voltage V(0)= -20V. The resulting current for t> 0 is: i(t) = 800e-25 μA Find: vo(t)t 20 -25t 800e μA :1.6 F O a. Vo(t) = +20 e-25t -40V o Vo(t) = -20 e-25t V Oc Vo(t) = +20 e 25t V O d. Vo(t) = -20 e 25t + 40 V Oe. None of these - Vo + Black BOX
Transcribed Image Text:The Capacitor connected across the terminals of a black box has an initial voltage V(0)= -20V. The resulting current for t> 0 is: i(t) = 800e-25 μA Find: vo(t)t 20 -25t 800e μA :1.6 F O a. Vo(t) = +20 e-25t -40V o Vo(t) = -20 e-25t V Oc Vo(t) = +20 e 25t V O d. Vo(t) = -20 e 25t + 40 V Oe. None of these - Vo + Black BOX
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