d the voltage and current of each capacitor and inductor in the circuit below ell 10 92 L₁ = 2 H :C₁ = 1 μF 592 C₂=2 μF HE ww 6Ω 30 V m L₂=6H 4Ω

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A:

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Q: O Calculate the equivalent capacitance if C₁ = 4 F C₂ = 6 F C3 = 1 F C₁ C3 C₂

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Q: How was the value of the capacitor derived?

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Q: For the circuit shown below the voltage across the capacitor is 102 -j100 2 (10+ j0) V ) j100 2

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Q: 5. Determine the total capacitance. 3 F 5F 6F CT 8F ISF

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Q: What is the reactance XL of the inductor? Is L 100mH Vs 2V 440HZ R 470Q

A: F = 440 Hz ω=2πF

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A: The circuit diagrams,

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A: The given circuit is shown below.The given values of the capacitances are shown below. F. F. F.

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Q: 8 µF 8 µF 12 µF a - 4 µF 3 µF 20 и bo

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Q: The total inductance for this circuit is mh. 5h L₂ 10 h L₂ 10 h

A: Given data, Circuit diagram is given as,

Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.