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Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.5: Comparing Sets Of Data

Problem 14PPS

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25-13-12
F X₁ X¹ A-AI A A A lab
What would be the "z-score" for a score of 28:
SOME SAMPLE SHORT ANSWER ITEMS:
The calculated value for your Chi Square crosstabulation comes in at 9.888. The test
has 4 degrees of freedom. Given a .05 alpha level, would you reject the null hypothesis?
What is the minimum calculated value necessary to reach the .01 alpha level with 3 degrees
of freedom in a Chi-Square cross-tabulation?
A SAMPLE MULTIPLE CHOICE ITEM:
The "confidence interval" lying between +1 SEM and -1 SEM would give us a "confidence
level" containing what percentage of the sample or population studied? (HINT: SEM stands
for "standard error of the mean.")
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Please help. State the hypothesis and identify the critical and z-values.
You are conducting a multinomial hypothesis test (αα = 0.05) for the claim that all 5 categories are equally likely to be selected. Category ObservedFrequency A 23 B 18 C 12 D 14 E 7 What is the chi-square test-statistic for this data?χ2=What are the degrees of freedom for this test?d.f. = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null accept the alternative As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected. There is not sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected. The sample data support the claim that all 5 categories are equally likely to be selected. There is not sufficient…
A multinomial experiment produced the following results: (You may find it useful to reference the appropriate table: chi-square table or F table) Category Frequency 2 3 4 5 70 42 72 64 62 a. Choose the appropriate alternative hypothesis to test if the population proportions differ. O All population proportions differ from 0.20. O Not all population proportions are equal to 0.20. b. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.) Test statistic c. Find the p-value. O 0.05 s p-value < 0.10 O 0.025 s p-value < 0.05 O 0.01 s p-value < 0.025 O p-value < 0.01 O p-value 2 0.10 d. Can we conclude at the 10% significance level that the population proportions are not equal? O No, since the p-value is less than the significance level. Yes, since the p-value is less than the significance level. O No, since the p-value is more than the significance level.
I randomly sample 219 students and ask them to provide their USF GPA. I wish to determine if the average GPA of all USF students ex mu + 3.25 ceeds 3.25. Unfortunately, I generated the printout shown here: One-Sample T Test Null Hypothesis: H - 3.25 Alternative Hyp: u- 3.25 Variable Mean SE DF GPA 3.3121 0.0340 1.82 218 0.0694 Cases Included 219 What assumption is needed for this analysis to be valid? None. The Central Limit Theorem applies and no other assumptions are needed. The GPAS of all USF students need to be approximately normally distributed The mean GPA of all USF students need to be approximately normally distributed
A report states the average temperature for the month of June on a specific tropical island is 98 degrees F. A meteorologist claims the report is not correct.. Data collected from 35 areas on the island showed an average temperature of 94 degrees F. Thepopulation standarddeviation is known to be 6.0 degrees F. At alpha = 0.05, can the report's average be rejected? For multiple choice question #1, tell what type of test: right-tailed, left-tailed, or two-tailed.

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