The accompanying data are measured body temperatures of adults at 12 AM on a certain day. Use the Wilcoxon signed-ranks test to test the claim that the median is equal to 98.6°F. Use a 0.05 significance level.Click the icon to view the body temperature data.Determine the null and alternative hypotheses.Ho: The median body temperature isH₁: The median body temperature is(Type integers or decimals. Do not round.)Determine the P-value.The P-value is(Round to three decimal places as needed.)Determine the proper conclusion.Ho. There is▼✔ evidence at the 0.05 significance level to warrant rejection of the claim that the median body temperature isC98.6°F.Body Temperature Data98.1 97.7 98.7 98.198.9 97.7 98.5 98.798.1 98.1 98.1 97.997.3 98.3 98.0 98.198.4 99.1 97.9 96.997.2 98.2 97.9 98.997.5 98.1 97.3 98.198.5 98.5 96.9 98.598.1 99.3 97.7 98.398.9 97.8 98.198.0 98.6 97.398.4 98.6 98 799.0 97.3 97.5 98.098.198.698.798.7 98.799.2 97.797.7 98.5 97.699.497.697.2 98.3 98.796.6 96.8 98.3 98.196.9 97.598.198.5 97.597.5 98.1PrintDone98.998.997.198.697.297.598.799.199.198.799.197.998.798.898.297.598.596.7- X

The data on the body temperature of adults is given as…

Answered: The accompanying data are measured body…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Your p value is .03 and you chose your α level to be .05. What kind of error could you be making? a. Type I error b. Type II error c. Type I and Type II error d. Neither errors
The data found below measure the amounts of greenhouse gas emissions from three types of vehicles. The measurements are in tons per year, expressed as CO2 equivalents. Use a 0.025 significance level to test the claim that the different types of vehicle have the same mean amount of greenhouse gas emissions. Based on the results, does the type of vehicle appear to affect the amount of greenhouse gas emissions? Click the icon to view the data. What are the hypotheses for this test? O A. Ho: At least one of the means is different from the others. H₁ H₁ H₂ H3 OB. Ho: H₁ H₁: H1 H₂ =H3 H₂ H3 OC. Ho: H₁ H₂ H3 H₁: At least one of the means is different from the others. O D. Ho: H₁ H₂ H3 H₁: H₁ H₂ =H3 Data Table Type A 6.2 6.2 6.5 7.4 7.1 6.1 6.9 7.3 6.9 6.7 Print C Type B 7.7 7.5 8.7 8.1 8.6 8.8 8.4 8.5 Type C 8.5 9.3 9.6 9.1 9.1 9.1 9.8 9.5 9.9 Done O X
The data found below measure the amounts of greenhouse gas emissions from three types of vehicles. The measurements are in tons per year, expressed as CO2 equivalents. Use a 0.05 significance level to test the claim that the different types of vehicle have the same mean amount of greenhouse gas emissions. Based on the results, does the type of vehicle appear to affect the amount of greenhouse gas emissions? Click the icon to view the data. What are the hypotheses for this test? OA. Ho: H₁ H₂ H3 H₁: H₁ H₂ H3 OB. Ho: H₁ H₂ =H3 H₁: At least one of the means is different from the others. O C. Ho: At least one of the means is different from the others. H₁: H₁=H₂ =H3 OD. Ho: H₁ H₂ H3 H₁: H1₁ H₂ H3 Determine the test statistic. F = (Round to two decimal places as needed.) Identify the P-value. P-value= (Round to two decimal places as needed.) What is the conclusion of the test? the null hypothesis. Conclude that the type of vehicle Data Table C Type A 6.5 6.2 6.5 6.5 5.8 7.5 6.4 6.4 6.2 6.9…
Each car in a random sample of 170 cars sold in 2010 at a large car dealership was classified by color. Sixty of the cars were white, 80 were blue, 20 were silver and 10 were red. What is the value of the chi-square test statistic in a test of Ho: Pw=Pb=Ps=Pr=0.25 A. 18 B. 32 C. 56 D. 77 E. 110
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1:37 PM Wed Apr 21 * 72% 88 Q Stats Exam •.. Untitled Notebook (1) Stats Exam 37. The manager of Green Valley medical center claims that the median number of patients seen by doctors who work at the center is 85. To test this claim, 20 days are randomly selected and the number of patients seen is recorded as shown. At a=0.1, test the claim. (Use sign test) 86 82 90 88 85 85 94 93 69 61 89 90 91 94 78 85 71 77 69 77
our p value is .03 and you chose your α level to be .05. What kind of error could you be making? a. Type I error b. Type II error c. Type I and Type II error d. Neither errors
State the conclusion based on the results of the test. The mean of the pressure required to open a certain valve is known to be u = 6.7 psi. Due to changes in the manufacturing process, the quality-control manager feels that the average pressure has changed. The null hypothesis was rejected. Choose the correct answer below. O A. The mean of the pressure has not changed. O B. There is not sufficient evidence that the mean of the pressure required to open a certain valve has changed. O C. There is not sufficient evidence that the mean of the pressure required to open a certain valve has not changed. O D. The mean of the pressure has changed. O E. There is sufficient evidence that the mean of the pressure required to open a certain valve has changed. O F. There is sufficient evidence that the mean of the pressure required to open a certain valve has not changed.
A poll classified respondents by gender and political party, as shown in the table. A researcher wonders if gender and party affiliation are not independent. (Assume a significance level of α = 0.05) Complete parts a) through e) below. d) Find the P-value for this test. Calculate the chi-square statistic. x² = 2.339 (Round to three decimal places as needed.) Find the P-value for the test. Choose the correct answer below. 0.0823 0.3104 0.003 DRIO 40 40 25 Male Female 49 35 18 e) State an appropriate conclusion. Choose the correct answer below. O A. Fail to reject the null hypothesis. There is sufficient evidence to support the claim. B. Reject the null hypothesis. There is not sufficient evidence to support the claim. C. Reject the null hypothesis. There is sufficient evidence to support the claim. O D. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim.
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)

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