ANSWER IS NOT 110 The calcium ion binds to a certain protein to form a 1:1 complex. The following data were obtained in an experiment.Total Ca2+/µM60.9122186250.536Ca2+ bound to Protein/µM31.451.463.671.083.6Determine graphically the dissociation constant of the Ca2+-protein complex. The protein concentration was kept at 97 µM for each run. (1 µM = 1x10-6 M.)%3DKd110

The binding of ligand to a receptor is one of the most important activity in cell. This activity leads to initiation of various functions in the cell. The binding of ligand to a protein is time dependent. As the time period increases, the ligand gets dissociated from the protein. However, the duration of binding depends on affinity of ligand and protein. The factor Kd is known as the dissociation constant, that is an equilibrium constant that controls equilibrium concentration of the dissociated ligand and protein to that of equilibrium concentration of ligand protein complex. In order to determine the dissociation constant Kd for Ca2+-protein binding, the concentration of Ca2+ ions that are unbound must be calculated. The total concentration of Ca2+is known. Similarly, the concentration of Ca2+ that is bound to protein is known. Therefore, the concentration of Ca2+ that is free is determined as the difference between total Ca2+ concentration and free Ca2+ concentration. Total Ca2+ ions Bound Ca2+ions Free Ca2+ions 60.9 31.4 60.9-31.4=29.5 122 51.4 70.6 186 63.6 122.4 250 71.0 179.0 536 83.6 452.4 Now the concentration of free Ca2+ is known. Let us represent the dissociation equation of Ca2+-protein complex as follows. Protein-Ca2+⇄KdProteinCa2+ Since the 1:1 complex is formed, the amount of Ca2+ ion that is free is same as amount of protein that is free. The dissociation constant can be obtained graphically using Scatchard equation and its plot. Ca2+BoundCa2+Free=Ca2+TotalKd-Ca2+BoundKd Therefore, the ratio of concentration of bound Ca2+ to free Ca2+ must be calculated. Total Ca2+ ions Bound Ca2+ions Free Ca2+ions Bound Ca2+/Free Ca2+ ions 60.9 31.4 29.5 1.064407 122 51.4 70.6 0.728045 186 63.6 122.4 0.519608 250 71.0 179.0 0.396648 536 83.6 452.4 0.184792 Now a graph is plotted between the ratio of bound Ca2+ to free Ca2+ in he y-axis and concentration of bound Ca2+ in x-axis. The equation of the line in the plot is of the form y=mx+c, which is similar to Scatchard equation. Therefore, the slope of the line gives the value of -1Kd. From the equation of the line y=-0.016x+1.593, the value of slope is -0.016. Therefore, the value of Kd can be calculated as follows. -1Kd=-0.016Kd=-1-0.016=62.5 Therefore, the value of Kd is 62.5.

Science

Chemistry

The calcium ion binds to a certain protein to form a 1:1 complex. The following data were obtained in an experiment. Total Ca2+/µM 60.9 122 186 250. 536 Ca²+ bound to Protein/µM 31.4 51.4 63.6 71.0 83.6 Determine graphically the dissociation constant of the Ca2+-protein complex. The protein concentration was kept at 97 µM for each run. (1 µM = 1×10-6 M.) Kg = 110

The calcium ion binds to a certain protein to form a 1:1 complex. The following data were obtained in an experiment. Total Ca2+/µM 60.9 122 186 250. 536 Ca²+ bound to Protein/µM 31.4 51.4 63.6 71.0 83.6 Determine graphically the dissociation constant of the Ca2+-protein complex. The protein concentration was kept at 97 µM for each run. (1 µM = 1×10-6 M.) Kg = 110

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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