The cable stays AB and AD help support pole AC. Khowing that the tension B 12016 in AB and 40 1b m AD, detemine graphically of the resutant of the Forces exertad the magnitude and directon by the catte stays at A Using 0:) parallelogram law b.) Triangle nue

I am having trouble with the folloiwng MATLAB code. I am getting an error that says "unrecognized function or variable 'numericalPropogatorOptions". I have the aerospace toolbox and the aerospace blockset added. what add on do I have to download to use that function. How do I make this code work?     % Define Keplerian Elements a = 29599.8; e = 0.0001; i = 0.9774; Omega = 1.3549; w = 0; M = 0.2645; [RECI, VECI] = Kepler2RV(a, e, i, Omega, w, M); initialState = [RECI * 1e3; VECI * 1e3]; % Initial position (m) and velocity (m/s)   % Define constants mu = 3.986004418e14; % Gravitational constant (m^3/s^2) earthRadius = 6378.1363 * 1e3; % Earth radius in meters j2 = 1.08263e-3; % J2 perturbation coefficient   % Define propagator options propOptions = numericalPropagatorOptions('CentralBody', 'Earth', ... 'GravitationalParameter', mu, ... 'InitialState', initialState, ... 'OutputTimeStep', 300); % Output every 300 seconds   % Add perturbations addGravityModel(propOptions, 'Degree', 2,…

K mylabmastering.pearson.com Chapter 12 - Lecture Notes.pptx: (MAE 272-01) (SP25) DY... P Pearson MyLab and Mastering Mastering Engineering Back to my courses Course Home Scores Course Home

MULTIPLE CHOICE -The answer is one of the options below please solve carefully and circle the correct option Please write clear .

I need help with the first part and Matlab for this problem

.com question/22816263 rch for an answer to any question... it works For parents For teachers Honor code 16 nours agO• Chemistry Hign Scnoo1 You are currently in a stable orbit 9000 km (1km=1000m) from the center of planet Proxima Centauri B. According to the calculations done by NASA, Planet Proxima Centauri B has a mass of approximately 7.6x10^24kg. Based on fuel consumption and expected material aboard the ship, your colony ship lander has a mass of approximately 1.1x10^5 kg. 1. Using Newton's Law of Universal Gravitation, determine what the force of gravity on your ship at that orbit be using the early measurements 2.Using Newton's second law determine the acceleration of your lander due to gravity 3.Upon arrival, you measure the actual force of gravity to be 6x10^5 N,which ic difforent from vourcalclated vauein cuection 1 ldentify 2cnocific e to search

I have attemped to start the question by first using the equation: log_{10}W_{TO} = A+Blog_{10}(CW_{TO} - D) After working out some stuff I got to: log_{10}W_{TO} = 0.833+1.0383log_{10}(CW_{TO} - 53000) Using the info give, C = M_ff I tried calculating the M_ff but needed the weight ratios for both cruises, loiter, and flight to another airport. I used the range and endurance equations for loiter and flight to another airport but cannot do cruise as I do not have the Mach number. I don't know how to continue.

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Could you please fix my code it’s supposed to look like the graph that’s on the picture. But the lines do not cross eachother at the beginning. Could you make the lines look like the lines on the graph? Use this code in MATLAB and fix it. % Sample data for Diesel and Petrol cars carPosition = linspace(1, 60, 50); % Assumed positions of cars % Define your seed here seed = 50; rand('seed',seed); % Set the seed for reproducibility % Assumed CO2 emissions for Diesel and Petrol CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol % Fit polynomial curves with a reduced degree of 2 pDiesel = polyfit(carPosition, CO2Diesel, 2); pPetrol = polyfit(carPosition, CO2Petrol, 2); % Generate points for best fit lines fitDiesel = polyval(pDiesel, carPosition); fitPetrol = polyval(pPetrol, carPosition); % Plotting the data figure; hold on; % Plot Diesel best fit line…

Can you write me a program manuscript using geometric definition on FAPT language. The starting point is P1 and starts where the blue dot is. P1 = 0,0