The bottlers of a new fruit juice daily select a random sample of 12 bottles of the drink to estimate the mean quantity of juice in the bottles filled that day. On one such day, a sample was taken with a sample mean of 12.03 and a sample standard deviation of 0.12. Based on this information, what is the margin of error associated with a 90 percent c

Q: A study of 36 golfers showed that their mean score at The Links at Arundel was 83.  The standard…

A: n=sample size= 36 X¯=sample mean=83σ=sample standard deviation=5 So the point estimate=X=83   Since…

Q: Suppose that shoe sizes of American women have a bell-shaped distribution with a mean of 8.47 and a…

A: Empirical rule: The probability that the observation under the normal curve lies within 1 standard…

Q: mpound and has built 16 tires and tested them to end-of-life in a road test. The sample san and…

A: Given n=16 Xbar=60139.7 S=3645.94 C=95%

Q: The number of cars sold annually by used car salespeople is normally distributed with a standard…

A: Given, Standard Deviation =σ=4.7Sample size =n = 47Mean = x=28

Q: Suppose you observe 77 data points from a distribution with standard deviation 8.4, and you…

A: Given that,  σ=8.4,n=77 Critical values: By using the z-table, the critical value at 92% confidence…

Q: In a random sample of eight ​people, the mean driving distance to work was 19.3 miles and the…

A: The question is about confidence interval Given : Randomly selected no. of people ( n ) = 8 Sample…

Q: A quality control manager wants to be sure that the standard deviation of oil containers is below a…

A: Let Xi be the amount of oil in the ith container,i=1,2,...,n.

Q: From the normally distributed systolic blood pressures of a given patient population with a standard…

A: Sample mean = x̅ = 120 Sample size = n = 9 Population S.D = σ = 24 Standard Error = σ/√n  =…

Q: were found to have an average weight of 9.7 ounces with a sample standard deviation is 0.20. Find…

A: As the population standard deviation is not known, we will use t distribution. Degrees of freedom…

Q: 5. A researcher surveyed of 300 young adults ages 18-29 found that on average, those surveyed sent…

A: 5. Given that, n=300x¯=67.7s=23.6 Confidence level=90% Significance level=1-0.90-0.10…

Q: In a random sample of 23 private school teachers in queens county the average teaching experience is…

A:

Q: Salaries of 33 college graduates who took a statistics course in college have a mean, x, of $69,000.…

A: Since we know population standard deviation, use z-distribution to find z-critical value. Find…

Q: the standard deviation of the 16 observations was 0.95 inches (again, the sample mean was 17.2).…

A: Given :  Standard deviation of the 16 observations was 0.95 inches & the sample mean was 17.2.…

Q: A report said that the average blood pressure is  130.71  for a sample of  37  white males aged  35…

A:

Q: A local police department made an effort to determine the average speed of automobiles travelling…

A:

Q: In a study entitled How Undergraduate Students Use Credit Cards, it was reported that undergraduate…

A: Given that, sample size n=100 sample mean credit card balance x¯=3506 Population standard deviation…

Q: The local Health Department conducted a study in 2009 of 900 adults asking each adult the number of…

A: Given Information: Sample size (n) = 900 Sample mean (x¯) = 7.946 Standard deviation = 6.567…

Q: Suppose that shoe sizes of American women have a bell-shaped distribution with a mean of 8.11 and a…

A: Given that the shoe sizes of American women have a bell-shaped distribution with a mean of 8.11 and…

Q: A study was commissioned to find the mean weight of the residents in certain town. The study…

A: Given: n=58, x=174 and s=38. Now,Degrees of freedom=n-1=58-1=57 Then, at 95% confidence level, the…

Q: 4) A study of 29 female Sumatran elephants provided a 96% confidence t-interval for the mean the…

A: Solution: 4. The standard error of the mean is calculated by using the formula:

Q: A random sample of 800 credit-card holders shows that the mean annual credit-card debt for…

A: Given information:  A random sample of n = 800 credit card holders was taken. The sample mean annual…

Q: An economist wants to estimate the average amount in savings account at banks in a given region. A…

A: Givensample size(n)=100Mean(x)=357.60standard deviation(s)=1.40confidence level = 95%

Q: Suppose a sample of 30 LCC students are given an IQ test. The sample has a standard deviation of…

A: Given the following information- n=30s=12.24s2=149.82

Q: At eight different locations, paint used to mark crosswalks deteriorated after being driven over by…

A: Solution: Let X be the number of cars that would cause deterioration. From the given information,…

Q: A sample of 48 observations is taken from a normal population with a standard deviation of 17. The…

A:

Q: Suppose that shoe sizes of American women have a bell-shaped distribution with a mean of 8.47 and a…

A:

Q: The lead levels in a random sample of 35 crows in the region were measured and recorded. The mean…

A: It is given that  Sample size n = 35 Sample mean M = 4.50 Sample SD s = 1.12 Confidence level = 99%…

Q: 13 squirrels were found to have an average weight of 790 grams with a sample standard deviation of…

A: Given that  n=13 , Mean=X̄=790 , Standard deviation=S=8.3 95% confidence interval

Q: 5.)  A recent study of 28 fantastic employees at KHS showed that their mean distance traveled from…

A: Solution : Given : Let, X : Distance travelled by employees from home to work            n = 28…

Q: Under the old method of postoperative treatment, the mean length of patients' hospital stay was 7.2…

A: It is given that: The sample size, n=165 The sample average duration (in days) of stay by the new…

Q: A sample of 9 production managers with over 15 years of experience has an average salary of $71,000…

A: The objective of this question is to determine the sample size needed to estimate the true mean…

Q: Suppose scores on exams in Biology are normally distributed with an unknown population mean and a…

A: given data σ = 5.4n = 60 x¯ = 81find 90% ci for μ = ?

Q: A sample of 22 public high school students spent an average of 6.5 hours studying per week. Assuming…

A:

Q: A sample of 500 observations is taken from a normally distributed population with a mean of 100 and…

A: A sample of 500 observations was taken from a normally distributed population.the standard deviation…

Q: The monthly advertising expenditure of the company is normally distributed with a standard deviation…

A:

Q: In an experimental study of the longevity of Drosophila melanogaster (fruit fly) 70 male adults and…

A: Solution: 1. State the hypotheses. Null hypothesis: That is, the male Drosophila not has a greater…

Q: Suppose you observe 62 data points from a distribution with standard deviation 2.1, and you…

A: Given, n=62 data points standard deviation SD= 2.1, calculated a 92% two-sided confidence interval…

Q: Find a 99% confidence interval for the mean of weights of Siamese cats if the population standard…

A: We have given that Sample mean (x̄) = 11.8, population standard deviation (σ) = 2.1 and sample size…

Q: has a mean life of 480 hours, construct a 99% confidence interval for the mean of the flashlights…

A: here population standard deviation  = 35 sample size  = 150  sample mean   = 480 and Z-critical for…