The bond dissociation energy to break 7 C-H bond(s) in 1 mole of propane (CH3CH,CH3) molecules is Single c N|0 O H Bond H 432 C 411 346 N 386 305 167 459 358 201 142
The bond dissociation energy to break 7 C-H bond(s) in 1 mole of propane (CH3CH,CH3) molecules is Single c N|0 O H Bond H 432 C 411 346 N 386 305 167 459 358 201 142
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Title: Calculating Bond Dissociation Energy for Propane**
**Introduction:**
The bond dissociation energy is a measure used to determine how much energy is required to break specific bonds within a molecule. In this example, we calculate the energy needed to break all the C-H bonds in a mole of propane (C₃H₈) molecules.
**Bond Dissociation Energy Table:**
The table below provides bond dissociation energy values for various single and multiple bonds. All values are given in kilojoules per mole (kJ/mol).
**Single Bonds:**
- H-H: 432
- H-C: 411
- H-N: 386
- H-O: 459
- C-C: 346
- C-N: 305
- C-O: 358
- N-N: 167
- N-O: 201
- O-O: 142
**Multiple Bonds:**
- C=C (double bond): 602
- C≡C (triple bond): 835
- C=O: 799
- C≡O: 1072
- C=N: 615
- C≡N: 887
- O=O: 494
- N≡N: 942
**Calculation:**
To calculate the total energy required to break all C-H bonds in 1 mole of propane:
- Propane has 8 hydrogen atoms resulting in 8 C-H bonds.
Using the H-C bond energy:
- Energy required = 7 bonds × 411 kJ/mol = 2877 kJ/mol
**Conclusion:**
By understanding bond dissociation energies, we can better comprehend molecular stability and the energy dynamics involved in chemical reactions. In the case of propane, substantial energy is required to break all its C-H bonds, reflecting its stability as a hydrocarbon.
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