The body temperatures of two species of geckos were measured. The n1 = 10 geckos from species A had a mean noon temperature of = 32.66°C and a %3D standard deviation of s1 = 0.81°C, whereas the n2 = 11 geckos from species %3D %3D B yielded mean = 30.12°C noon temperature and s2 = 0.75°. To test the %3D %3D hypothesis of no difference versus the alternative of a difference in mean noon temperature at the 5% level of significance, one would need to calculate the t-calculated value. What are the t calculated and t critical values? Calculated = 7.46; Critical = 2.776 Calculated = -3.458; Critical = 2.080 Calculated = 7.46; Critical = 2.093 Calculated = -3.458; Critical = 2.776
The body temperatures of two species of geckos were measured. The n1 = 10 geckos from species A had a mean noon temperature of = 32.66°C and a %3D standard deviation of s1 = 0.81°C, whereas the n2 = 11 geckos from species %3D %3D B yielded mean = 30.12°C noon temperature and s2 = 0.75°. To test the %3D %3D hypothesis of no difference versus the alternative of a difference in mean noon temperature at the 5% level of significance, one would need to calculate the t-calculated value. What are the t calculated and t critical values? Calculated = 7.46; Critical = 2.776 Calculated = -3.458; Critical = 2.080 Calculated = 7.46; Critical = 2.093 Calculated = -3.458; Critical = 2.776
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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![The body temperatures of two species of geckos were measured. The n =
%3D
10 geckos from species A had a mean noon temperature of = 32.66°C and a
standard deviation of s1 = 0.81°C, whereas the n2 = 11 geckos from species
%3D
B yielded mean = 30.12°C noon temperature and s2 = 0.75°. To test the
%3D
hypothesis of no difference versus the alternative of a difference in mean
noon temperature
the 5% level of significance, one would need to
calculate the t-calculated value.
What are thet calculated and t critical values?
Calculated = 7.46; Critical = 2.776
%3D
%3D
Calculated = -3.458; Critical = 2.080
%3D
%3D
Calculated = 7.46; Critical = 2.093
Calculated = -3.458; Critical = 2.776](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5a331355-eac3-437e-bec7-6442c8371e3e%2F4ceba3f7-0041-47c7-b3cd-ebd519990c87%2F7yedg2f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The body temperatures of two species of geckos were measured. The n =
%3D
10 geckos from species A had a mean noon temperature of = 32.66°C and a
standard deviation of s1 = 0.81°C, whereas the n2 = 11 geckos from species
%3D
B yielded mean = 30.12°C noon temperature and s2 = 0.75°. To test the
%3D
hypothesis of no difference versus the alternative of a difference in mean
noon temperature
the 5% level of significance, one would need to
calculate the t-calculated value.
What are thet calculated and t critical values?
Calculated = 7.46; Critical = 2.776
%3D
%3D
Calculated = -3.458; Critical = 2.080
%3D
%3D
Calculated = 7.46; Critical = 2.093
Calculated = -3.458; Critical = 2.776
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