The body in the figure is pivoted at O. Three forces act on it: FA = 10N at point A, 8.0m from O; FB = 16N at point B, 4.0m from O; and FC = 19N at point C, 3.0m from O. What is the net torque about O? I am using the formulas: tauA = FArA sin thetaA = (10)(8.0) sin 1350;  tauB = FBrB sin thetaB = (16)(4.0) sin 900;

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Chapter1: Units, Trigonometry. And Vectors
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The body in the figure is pivoted at O. Three forces act on it: FA = 10N at point A, 8.0m from O; FB = 16N at point B, 4.0m from O; and FC = 19N at point C, 3.0m from O. What is the net torque about O?

I am using the formulas: tauA = FArA sin thetaA = (10)(8.0) sin 1350;  tauB = FBrB sin thetaB = (16)(4.0) sin 900;

tauC = FCrC sin thetaC = (19)(3.0) sin 1600

So, I can find the magnitudes of the three torques (tauA, tauB, and tauC). I do not know how to determine their signs, that is, how to determine the direction of the rotation (clockwise or counterclockwise). Please explain what is the axis of rotation here, and how to determine the direction of the rotation (clockwise or counterclockwise) for this problem specifically and in general.

FA
Fc
135
C
160°
90°
FB
B
Transcribed Image Text:FA Fc 135 C 160° 90° FB B
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