Given, TT = TlT = Tlsin(0), at what angle ) will torque be maximized? O deg 30 deg 60 deg 90 deg
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Q: Given, Tr = Tlr = Tlsin(0), at what angle 0 will torque be maximized?
A: As we know.. torque = r×F torque = rFSin(theta) ;
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A: Rotational mechanics.
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Q: Find the net torque on the wheel in Figure about the axle through O, taking a=10.0 cm and b=25.0 cm.
A: Given the value of 'a' = 10 cm. Given the value of 'b' = 25 cm.
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- Two wheels of moment of inertia 9.7 kg.m and 9.4 kg.m are set in rotation with angular speed 21 rad/s and 1.9 rad/s, respectively. When they are coupled face to face (as shown in the following figure) they rotate with a common angularspeed co due to frictional forces, then what is the change in kinetic energy 0) of the wheels due to frictional forces? Before coupling After coupling Select one O 20.10 O h-o.19 O c-010 vith d.019Determine the moment of inertia and the product of ineria for the area ifor the figure above with respect to new centroial axex obtained by rotating the x and y axes 30o counterclockwise. Answer: Ix’= 2.12x106 mm4, Iy’ = 8.28x106 mm4, and Ix’y’ = 0.532x106 mm4The wheels of a wagon can be approximated as the combination of a thin outer hoop, of radius ?h=0.421 m and mass 5.46 kg, and two thin crossed rods of mass 7.37 kg each. A farmer would like to replace his wheels with uniform disks ?d=0.0588 mthick, made out of a material with a density of 5990 kg per cubic meter. If the new wheel is to have the same moment of inertia about its center as the old wheel about its center, what should the radius of the disk be?
- A thin rod of mass M and length L is pivoted on a frictionless hinge at one end, as shown. The rest horizontally and then released. Gravity acts on the rod and accelerates it. What is the angular acceleration of the rod right after the release, ao, and what is it when it passes the vertical position, a(5)? (A) ao 3D a(플) %3D0 (B) ao %3D 유 and a(품) %3D0 (C) ao = and a() = (D) ao 3D and a(품) %3D0 CM (E) ao %3D and a(플) %3D우 (F) ao %3D D and a(플) %3D¥ A thin rod with a hinge at one end released from rest from the horizontal position.Why is the third torque negative?The body in the figure is pivoted at O. Three forces act on it in the directions shown: FA = 11.0 N at point A, 8.20 m from O; FB = 19.0 N at point B, 4.30 m from O; and FC = 16.0 N at point C, 2.40 m from O. Taking the clockwise direction to be negative, what is the net torque about O?
- A solid ssphere of radius 25cm & mass 25kg ro fater about an axis through its center. Calculate its moment of inertia of its angulal velocity changes from 2 rad/s to 12 rads in 5 second. Also calculate torque applied?spokes Ave negligile mass. (o) What is the net torque on the rystem about the axie of the pullew? magnitude \[ N=m \] dicectien2a+m)2Find the torque about the point (1, −2, 1) due to the force F = 2i − j + 3k acting at the point (1, 1, −3).