The Blue Diamond Company advertises that their nut mix contains (by weight) 40% cashews, 15% Brazil nuts, 20% almonds and only 25% peanuts. The truth-in-advertising investigators took a random sample (of size 20 lbs) of the nut mix and found the distribution to be as follows: 5 lbs of Cashews, 6 lbs of Brazil nuts, 6 lbs of Almonds and 3 lbs of Peanuts. At the 0.05 level of significance, is the claim made by Blue Diamond true? Select the [p-value, Decision to Reject (RH0) or Failure to Reject (FRH0)]. a) [p-value = 0.015, RH0] b) [p-value = 0.115, RH0] c) [p-value = 0.115, FRH0] d) [p-value = 0.015, FRH0] e) [p-value = 0.058, RH0]
The Blue Diamond Company advertises that their nut mix contains (by weight) 40% cashews, 15% Brazil nuts, 20% almonds and only 25% peanuts. The truth-in-advertising investigators took a random sample (of size 20 lbs) of the nut mix and found the distribution to be as follows: 5 lbs of Cashews, 6 lbs of Brazil nuts, 6 lbs of Almonds and 3 lbs of Peanuts. At the 0.05 level of significance, is the claim made by Blue Diamond true? Select the [p-value, Decision to Reject (RH0) or Failure to Reject (FRH0)]. a) [p-value = 0.015, RH0] b) [p-value = 0.115, RH0] c) [p-value = 0.115, FRH0] d) [p-value = 0.015, FRH0] e) [p-value = 0.058, RH0]
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The Blue Diamond Company advertises that their nut mix contains (by weight) 40% cashews, 15% Brazil nuts, 20% almonds and only 25% peanuts. The truth-in-advertising investigators took a random sample (of size 20 lbs) of the nut mix and found the distribution to be as follows: 5 lbs of Cashews, 6 lbs of Brazil nuts, 6 lbs of Almonds and 3 lbs of Peanuts. At the 0.05 level of significance, is the claim made by Blue Diamond true?
Select the [p-value, Decision to Reject (RH0) or Failure to Reject (FRH0)].
Select the [p-value, Decision to Reject (RH0) or Failure to Reject (FRH0)].
a) [p-value = 0.015, RH0]
b) [p-value = 0.115, RH0]
c) [p-value = 0.115, FRH0]
d) [p-value = 0.015, FRH0]
e) [p-value = 0.058, RH0]
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